var data = { "title1": {"subtitle1": "one", "subtitle2": "two"}, "title2": "three", "title3": "four" };
我可以使用：
for (var key in data) {
console.log(key);
}
要獲取：
title1
title2
title3
我可以使用：
var key = Object.keys(data)[0];
for (var prop in data[key]){
console.log(data[key][prop]);
}
要獲取：
one
two
問：我可以用什麼來獲得：
one
two
three
four
試試這個
var data = {
"title1": {
"subtitle1": "one",
"subtitle2": "two"
},
"title2": "three",
"title3": "four"
};
var output = [];
Object.keys(data).forEach(function(key) {
if (typeof data[key] == "object") {
Object.keys(data[key]).forEach(function(innerKey) {
output.push(data[key][innerKey])
});
} else {
output.push(data[key]);
}
});
console.log(output);什麼你要找的是一個遞歸循環。從this SO page:
function eachRecursive(obj)
{
for (var k in obj)
{
if (typeof obj[k] == "object" && obj[k] !== null)
eachRecursive(obj[k]);
else
console.log(k, obj[k]);
}
}
（8號線在這裏，你做你的東西，在這種情況下，我退出鍵和值）
您coud使用迭代遞歸方法吧。
function iter(object) {
Object.keys(object).forEach(function (k) {
if (typeof object[k] === 'object') {
iter(object[k]);
return;
}
console.log(object[k]);
});
}
var data = { "title1": { "subtitle1": "one", "subtitle2": "two" }, "title2": "three", "title3": "four" };
iter(data);你可以試試這個
var data = { "title1": {"subtitle1": "one", "subtitle2": "two"}, "title2": "three", "title3": "four" };
function getValues(obj) {
var values=[]
if (obj){
Object.keys(obj).forEach(function (key) {
if (typeof obj[key] == "object"){
values.push(getValues(obj[key]));
}else {
values.push(obj[key])
}
});
}
return [].concat.apply([], values);
}
console.log(getValues(data))
您可以使用遞歸函數深入挖掘對象層次結構，並列出所有需要的格式的所有值。這種東西
function getValues(obj) {
var returnVal = '';
if (obj !== null) {
if (typeof obj === 'object') {
Object.keys(obj).forEach(function(key) {
returnVal = returnVal + getValues(obj[key]) + '\n';
});
} else {
returnVal = returnVal + obj + '\n';
}
}
return returnVal;
}
var data = {
"title1": {
"subtitle1": "one",
"subtitle2": "two"
},
"title2": "three",
"title3": "four"
};
console.log(getValues(data));如果你想成爲更通用的數據結構，你可以使用JSONPath直接訪問JSON葉子：
當Xpath的所有葉表達//*[not(*)]，而在JSONPath中這變成了$..[?(@.length>=0)]，所以你有
function jsonPath(obj,expr,arg){var P={resultType:arg&&arg.resultType||"VALUE",result:[],normalize:function(e){var t=[];return e.replace(/[\['](\??\(.*?\))[\]']/g,function(e,r){return"[#"+(t.push(r)-1)+"]"}).replace(/'?\.'?|\['?/g,";").replace(/;;;|;;/g,";..;").replace(/;$|'?\]|'$/g,"").replace(/#([0-9]+)/g,function(e,r){return t[r]})},asPath:function(e){for(var t=e.split(";"),r="$",a=1,n=t.length;n>a;a++)r+=/^[0-9*]+$/.test(t[a])?"["+t[a]+"]":"['"+t[a]+"']";return r},store:function(e,t){return e&&(P.result[P.result.length]="PATH"==P.resultType?P.asPath(e):t),!!e},trace:function(e,t,r){if(e){var a=e.split(";"),n=a.shift();if(a=a.join(";"),t&&t.hasOwnProperty(n))P.trace(a,t[n],r+";"+n);else if("*"===n)P.walk(n,a,t,r,function(e,t,r,a,n){P.trace(e+";"+r,a,n)});else if(".."===n)P.trace(a,t,r),P.walk(n,a,t,r,function(e,t,r,a,n){"object"==typeof a[e]&&P.trace("..;"+r,a[e],n+";"+e)});else if(/,/.test(n))for(var l=n.split(/'?,'?/),s=0,c=l.length;c>s;s++)P.trace(l[s]+";"+a,t,r);else/^\(.*?\)$/.test(n)?P.trace(P.eval(n,t,r.substr(r.lastIndexOf(";")+1))+";"+a,t,r):/^\?\(.*?\)$/.test(n)?P.walk(n,a,t,r,function(e,t,r,a,n){P.eval(t.replace(/^\?\((.*?)\)$/,"$1"),a[e],e)&&P.trace(e+";"+r,a,n)}):/^(-?[0-9]*):(-?[0-9]*):?([0-9]*)$/.test(n)&&P.slice(n,a,t,r)}else P.store(r,t)},walk:function(e,t,r,a,n){if(r instanceof Array)for(var l=0,s=r.length;s>l;l++)l in r&&n(l,e,t,r,a);else if("object"==typeof r)for(var c in r)r.hasOwnProperty(c)&&n(c,e,t,r,a)},slice:function(e,t,r,a){if(r instanceof Array){var n=r.length,l=0,s=n,c=1;e.replace(/^(-?[0-9]*):(-?[0-9]*):?(-?[0-9]*)$/g,function(e,t,r,a){l=parseInt(t||l),s=parseInt(r||s),c=parseInt(a||c)}),l=0>l?Math.max(0,l+n):Math.min(n,l),s=0>s?Math.max(0,s+n):Math.min(n,s);for(var o=l;s>o;o+=c)P.trace(o+";"+t,r,a)}},eval:function(x,_v,_vname){try{return $&&_v&&eval(x.replace(/@/g,"_v"))}catch(e){throw new SyntaxError("jsonPath: "+e.message+": "+x.replace(/@/g,"_v").replace(/\^/g,"_a"))}}},$=obj;return expr&&obj&&("VALUE"==P.resultType||"PATH"==P.resultType)?(P.trace(P.normalize(expr).replace(/^\$;/,""),obj,"$"),P.result.length?P.result:!1):void 0}
// some extensions I have added to JSONPath
var jsonPathStore = function(obj,path,values) {
var maps=jsonPath(obj, path,{resultType:"PATH"})
maps.map(function(item,index) {
return eval('(' + item.replace(/\$/,"obj") + '="' + values[index] +'"' + ')');
})
}
var jsonPathDelete = function(obj,path) {
var maps=jsonPath(obj, path,{resultType:"PATH"})
maps.map(function(item,index) {
return eval('(' + 'delete ' + item.replace(/\$/,"obj") + ')');
})
}
var jsonPathRead = function(obj,path) {
var maps=jsonPath(obj, path,{resultType:"PATH"})
return maps.map(function(item,index) {
return eval('(' + item.replace(/\$/,"obj") + ')');
})
}
var data = { "title1": {"subtitle1": "one", "subtitle2": "two"}, "title2": "three", "title3": "four" };
//
// xpath all leaf expression is //*[not(*)]
// in jspath becomes $..[?(@.length>=0)]
var jsonObjectLeafValues =
jsonPathRead(data,"$..[?(@.length>=0)]");
// this XPath will read all the id properties starting from the root element
console.log(JSON.stringify(jsonObjectLeafValues, null, 2))此json路徑版本是從原始版本改編的，它可用here。
謝謝，這個作品很棒。所以forEach函數只作用於數組的每個元素？感謝大家誰迴應 – fivedoor
@fivedoor是，在這種情況下，數組的元素是關鍵。 – gurvinder372