添加元素只有在newDict
去除僅在oldDict
var intersection = newDict.Keys.Intersect(oldDict.Keys);
var added = newDict.Keys.Except(intersection);
var removed = oldDict.Keys.Except(intersection);
編輯
我修改你的基地功能,字典是沒有neded。
例UserInvolvement
實施
class UserInvolvement
{
public int UserId;
public string Name;
public string OtherInfo;
public override bool Equals(object obj)
{
if (obj == null)
{
return false;
}
UserInvolvement p = obj as UserInvolvement;
if ((System.Object)p == null)
{
return false;
}
return (UserId == p.UserId) && (Name == p.Name) && (OtherInfo == p.OtherInfo);
}
public override string ToString()
{
return $"{UserId} - {Name} - {OtherInfo}";
}
}
而且例如功能:
private static string GetInvolvementLogging(ICollection<UserInvolvement> newInvolvement,
ICollection<UserInvolvement> oldInvolvement)
{
var intersection = newInvolvement.Select(x => x.UserId).Intersect(oldInvolvement.Select(x => x.UserId));
var addedIds = newInvolvement.Select(x => x.UserId).Except(intersection);
var removedIds = oldInvolvement.Select(x => x.UserId).Except(intersection);
List<UserInvolvement> modifiedUI = new List<UserInvolvement>();
foreach (var i in intersection)
{
var ni = newInvolvement.First(a => a.UserId == i);
var oi = oldInvolvement.First(a => a.UserId == i);
if (!ni.Equals(oi))
{
modifiedUI.Add(ni);
}
}
List<UserInvolvement> addedUI = newInvolvement.Where(x => addedIds.Contains(x.UserId)).Select(w => w).ToList();
List<UserInvolvement> removedUI = oldInvolvement.Where(x => removedIds.Contains(x.UserId)).Select(w => w).ToList();
StringBuilder sb = new StringBuilder();
sb.AppendLine("Added");
foreach (var added in addedUI)
{
sb.AppendLine(added.ToString());
}
sb.AppendLine("Removed");
foreach (var removed in removedUI)
{
sb.AppendLine(removed.ToString());
}
sb.AppendLine("Modified");
foreach (var modified in modifiedUI)
{
sb.AppendLine(modified.ToString());
}
return sb.ToString();
}
而我的測試功能:
static void Main(string[] args)
{
List<UserInvolvement> newUI = new List<UserInvolvement>()
{
new UserInvolvement()
{
UserId = 1,
Name = "AAA",
OtherInfo = "QQQ"
},
new UserInvolvement()
{
UserId = 2,
Name = "BBB",
OtherInfo = "123"
},
new UserInvolvement()
{
UserId = 4,
Name = "DDD",
OtherInfo = "123ert"
}
};
List<UserInvolvement> oldUI = new List<UserInvolvement>()
{
new UserInvolvement()
{
UserId = 2,
Name = "BBBC",
OtherInfo = "123"
},
new UserInvolvement()
{
UserId = 3,
Name = "CCC",
OtherInfo = "QQ44"
},
new UserInvolvement()
{
UserId = 4,
Name = "DDD",
OtherInfo = "123ert"
}
};
string resp = GetInvolvementLogging(newUI, oldUI);
WriteLine(resp);
ReadKey();
WriteLine("CU");
}
結果是:
Added
1 - AAA - QQQ
Removed
3 - CCC - QQ44
Modified
2 - BBB - 123
來源
2017-05-26 12:58:24
BWA
認爲最簡單和天真的算法應該沒問題。迭代每個字典並檢查另一個字典中是否存在項目 – tym32167
如果列表中的條目發生更改,會發生什麼情況 - 即密鑰是否都在兩個列表中,這兩個參與值都不同? – PaulF
@PaulF,好問題!參與是一個枚舉標誌。值的變化意味着標誌已被添加和刪除。我希望那些反映在Dictionary中。 –