使用while循環計算列表中的元素

Question

places = [ "Jack", "Jo hn", "Sochi", "Manan", "Mayank"] 
count=0 
multi_word=0 
place = places[count] 
while place != "Sochi" : 
    if ' ' in place: 
     multi_word += 1 

    count += 1 
    place = places[count] 

print ('Number of cities before Sochi:', count) 
print ('Number of multiple names cities before Sochi:', multi_word) 

這是我的代碼我不明白這一行（place = places [count]）是幹什麼的，我也不明白爲什麼我需要它兩次。

它是否使程序從Jack開始，然後在到達列表的下一個元素（Jo hn）時添加1，並且在Sochi之後再添加一個並停止，或者在第一個元素處添加一個列表，然後停止一旦到達索契。

Answer 1

你的算法可表示爲如下：

places = [ "Jack", "Jo hn", "Sochi", "Manan", "Mayank"] 
#Set the number of multiword to 0 
multi_word=0 
#Take the first element from the list as place 
count=0 
place = places[count] 
#If place is "Sochi" we're done 
while place != "Sochi" : 
    #Check if place is a multiword 
    if ' ' in place: 
     multi_word += 1 
    #Move to the next element 
    count += 1 
    place = places[count] 

第一次計數等於0，使得線基本上採取第一元件 然後，在循環內，計數遞增，並且下一個元素是取自列表 當地點等於「Sochi」時，迭代停止，這意味着「Sochi」和任何後面的元素都不會被檢查。

這真是令人困惑和寫得不好。這裏有一個更簡單的版本

place_list = [ "Jack", "Jo hn", "Sochi", "Manan", "Mayank"] 
multi_word_count = 0 
place_index = 0 
while True: 
    current_place = place_list[index] 
    if current_place == "Sochi": 
     break 
    if ' ' in current_place: 
     multi_word_count += 1 
    place_index += 1 

現在，這裏是一個更好的解決方案

place_list = [ "Jack", "Jo hn", "Sochi", "Manan", "Mayank"] 
multi_word_count = 0 

for place in place_list: 
    if place == "Sochi": 
     break 
    if ' ' in current_place: 
     multi_word_count += 1