關於事件的Openfile

Question

我正在用VB.Net編程（全新手）弄溼我的腳。我有一個包含其他信息的DataGridView，一個存儲特定文檔的文件路徑。我已經將DataGridViewButtonColumn添加到DataGridView，但我無法弄清楚如何讓按鈕打開文件。

對不起，我沒有代碼提供作爲我卡住的地方的起點。

由於提前，

Answer 1

對不起，我沒有閱讀後足夠清晰的第一次，並沒有足夠的解釋我的代碼，所以它刪除了。這使用contentclick事件。

Dim Filetext As String = "" 'At start of the class to make it available to the whole class 

Private Sub DataGridView1_CellContentClick(sender As System.Object, e As System.Windows.Forms.DataGridViewCellEventArgs) Handles DataGridView1.CellContentClick 
Dim FilePathColumn As Integer = 0 'File path is in Column 0 
Dim ButtonColumn As Integer = 1 'Column buttons are in 
Dim RowClicked As Integer = e.RowIndex 'This gets the row that you clicked the button in 

If e.ColumnIndex = ButtonColumn Then 'Make sure you clicked a button 
    Dim FILE_PATH As String = DataGridView1.Rows(RowClicked).Cells(FilePathColumn).ToString 'Get the path to the file 
    If System.IO.File.Exists(FILE_PATH) Then 'Make sure file exists 
     Filetext = System.IO.File.ReadAllText(FILE_PATH) 'Save file to a variable 

     'OR 

     Process.Start(FILE_PATH) 'To open it 
    End If 
End If 
End Sub 

可以擺脫那些最行，但我寫的那樣來解釋它是如何工作