將UIPickerView選擇存儲到變量中

Question

如何將UIPickerView選擇存儲到變量中？

func pickerView(pickerView: AKPickerView, didSelectItem item: Int) { 
} 

let selected = pickerView(samplePickerView, what goes here?) 

Answer 1

首先你會拿着一個數組我猜。所以讓我們將它命名爲pickerarray，並將它作爲一個字符串數組。

func pickerView(pickerView: UIPickerView!, didSelectRow row: Int, inComponent component: Int){ 
    selected = pickerarray[row] // selected is the variable 
} 

這裏您使用的是pickerview的row屬性。

編輯 爲了您的澄清，我進入整個代碼

import UIKit 


class ViewController: UIViewController, UIPickerViewDataSource,UIPickerViewDelegate { 

@IBOutlet var MyPickerView: UIPickerView! 
var selected = "" 
let words: NSArray = ["Cat", "Chicken", "fish", "Dog", 
    "Mouse", "Guinea Pig", "monkey"] 

override func viewDidLoad() { 
    super.viewDidLoad() 
    MyPickerView.delegate = self 
    MyPickerView.dataSource = self 

    selected = words[0] // setting the default value 

} 
func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int { 
    return words.count 
} 
func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? { 
    return "\(words[row])" 
} 
func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) { 
    selected = words[row] as! String 
} 
func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int { 
    return 1 
} 

override func didReceiveMemoryWarning() { 
    super.didReceiveMemoryWarning() 
    // Dispose of any resources that can be recreated. 
} 
} 

從pickerview從任何函數訪問選定的值，使用

let selectedvalue = selected