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我正在嘗試執行SOAP請求,但服務器正在返回500錯誤。 SOAP請求例如通過Jmeter正確地返回XML消息,所以它必須是我的代碼中的某些東西,但是我看不到什麼。你能幫我嗎?執行SOAP請求時發生內部服務器錯誤(500)
private void soapRequest(string regID)
{
string soapReq= @"<?xml version=""1.0"" encoding=""utf-8""?>";
soapReq= "<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:mpc=\"urn://mobility-platform.de/mpcustomerdb/\">\n";
soapReq += "<soapenv:Header/>\n";
soapReq += "<soapenv:Body>\n";
soapReq += "<mpc:findRegistrationByID>\n";
soapReq += "<registrationID>" + regID + "</registrationID>\n";
soapReq += "</mpc:findRegistrationByID>\n";
soapReq += "</soapenv:Body>\n";
soapReq += "</soapenv:Envelope>";
//Builds the connection to the WebService.
HttpWebRequest req = (HttpWebRequest)WebRequest.Create("http://url?wsdl");
req.Credentials = new NetworkCredential("user", "pass");
req.Headers.Add("SOAP:Action");
req.ContentType = "text/xml;charset=\"utf-8\"";
req.Accept = "text/xml";
req.Method = "POST";
//Passes the SoapRequest String to the WebService
using (Stream stm = req.GetRequestStream())
{
using (StreamWriter stmw = new StreamWriter(stm))
{
stmw.Write(soapReq.ToString());
}
}
try
{
//Gets the response
HttpWebResponse soapResponse = (HttpWebResponse)req.GetResponse();
//Writes the Response
Stream responseStream = soapResponse.GetResponseStream();
//read the stream
XmlDocument soapResponseXML = new XmlDocument();
StreamReader responseStreamRead = new StreamReader(responseStream);
soapResponse.ContentType = "text/xml";
//MessageBox.Show(responseStreamRead.ReadToEnd().ToString());
string soapURL = responseStreamRead.ReadToEnd().ToString();
soapResponseXML.LoadXml(soapURL);
}
catch (Exception ex)
{
MessageBox.Show("Error: " + ex.Message);
}
}
這裏是SOAP請求
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:mpc="urn://mobility-platform.de/mpcustomerdb/">
<soapenv:Header/>
<soapenv:Body>
<mpc:findRegistrationByID>
<registrationID>2304580</registrationID>
</mpc:findRegistrationByID>
</soapenv:Body>
</soapenv:Envelope>
後來編輯: 如果我改變
req.Headers.Add("SOAP:Action");
到:
req.Headers.Add("SOAPAction", ""\"http://url\"" + "findRegistrationByID");
我得到一個不同的錯誤: 「這個屬性沒有被這個類實現」
**一)**切勿從字符串構建XML 。 ** b)**您的'req.Accept =「text/xml」;'可能是錯誤的。什麼'Content-Type'服務器返回成功的響應?這是你應該設置'接受'的人。 – Tomalak 2012-03-15 11:18:18
你有權訪問有問題的服務器嗎?如果是這樣,應用程序日誌中的事件查看器應該有一些有用的信息。 – 2012-03-15 13:04:46
我想我在這裏做錯了:'req.Headers.Add(「SOAP:Action」);'它應該是這樣的:'req.Headers.Add(「SOAPAction」,「」\「http://url \「」+「findRegistrationByID」);'但是如果我改變它就像我得到以下錯誤**此屬性不是由這個類實現** – observ 2012-03-15 14:46:24