休眠濾波器session.get的情況下不工作（），但在session.createQuery的情況下工作（）

Question

我使用休眠4.我寫一個過濾器。我注意到奇怪的是沒有得到應用的過濾器，如果我使用session.get（）方法

public SecurityAgency getSecurityAgencyById(int id) { 
     Session session = this.sessionFactory.getCurrentSession(); 
     session.enableFilter("byEnabled"); 
     SecurityAgency s = (SecurityAgency)session.get(SecurityAgency.class, new Integer(id)); 

     return s; 
    } 

濾鏡開始，只要我更換session.createQuery方法session.get方法和發送工作HQL查詢。我無法在hibernate文檔中找到任何此行爲的原因。在securtiy代理類

filter聲明

@Entity 
@Table(name="security_agency") 

public class SecurityAgency implements java.io.Serializable { 
@Id 
@Column(name = "id") 
@GeneratedValue(strategy = GenerationType.IDENTITY) 
private int id; 
@Column(name="name") 
private String name; 
@Column(name="code") 
private String code; 
@Column(name="website") 
private String website; 
@Column(name="tan") 
private String tan; 
@Column(name="email") 
private String email; 
@Column(name="pan") 
private String pan; 
@Column(name="created_at") 
private Date createdAt; 
@Column(name="created_by") 
private long createdBy; 
@Column(name="modified_at") 
private Date modifiedAt; 
@Column(name="modified_by") 
private long modifiedBy; 
@OneToMany(mappedBy="securityAgency",fetch = FetchType.EAGER) 
@JsonIgnoreProperties("securityAgency") 

@Filter(name = "byEnabled", condition = "is_enabled= 1") 
private Set<ContactPerson> contactPersons = new HashSet<ContactPerson>(0); 

public SecurityAgency() { 
} 

聯繫人類

@Entity 
@Table(name = "contact_person") 
@FilterDefs({ 
    @FilterDef(name="byEnabled"), 
    @FilterDef(name="bySecurityAgency",parameters =  @ParamDef(name="agency_id", type="int")) 
}) 
@Filters({ 
    @Filter(name="byEnabled", condition = "is_enabled = 1"), 
    @Filter(name="bySecurityAgency", condition = "agency_id= :agency_id ") 
}) 
public class ContactPerson implements java.io.Serializable { 

Answer 1

，如果你想使用的表列的值，你需要使用過濾器聯接表（@FilterJoinTable），@Filter是適用於目標實體而非表格

嘗試，

@FilterJoinTable(name = "byEnabled", condition = "is_enabled= :enabled") 
private Set<ContactPerson> contactPersons = new HashSet<ContactPerson>(0); 

得到，如果你正在使用的ID value.Use查詢接口，而不是獲取

session.enableFilter("byEnabled").setParameter("enabled", Integer.valueOf(1)); 

Answer 2

過濾器不起作用。請參閱this thread