這是我們合作伙伴分配的運行長度編碼程序。

Question

我們正在嘗試對Javadoc進行指導。到目前爲止，我們有這一點，但感到困惑與指數放慢參數

* Read the next run (or single character) and return the index of the symbol following the run (or symbol read). 
    * Store the count and symbol for the run in the run parameter. 
    * @param line - the input line being processed 
    * @param index - the index of the first character in the next "run" (which might be just a single character) 
    * @param run - where to store the symbol and count for the Run 
    * @return the index of the symbol following the run just read 
    */ 
    static int getNext(String line, int index, Run run) { 
    line.charAt(index); //char first, something about a line 
    return ?.symbol;//Store values 
    run.count= ?.count; //the given number of that specific symbol or repetition 
    enter code here 
    run.symbol= ?.symbol; //whatever symbol you first see 
    // TO BE COMPLETED 

    return index+1;// just to make it advance so starter program doesn't loop infinitely 
    } 
} 

Answer 1

這不是實際的RLE壓縮功能，而是一個輔助函數來計算正由主RLE處理當前字符的重複壓縮功能。

什麼，這似乎需要做的是這樣的：

• 以字符字符串時的line指數index，並將其存儲在運行對象的相應屬性。
• 在索引index之後，對line中的字符進行迭代，直至遇到與您在開始時所用的字符不相同的字符。
• 將找到的重複數量存儲在Run對象的相應屬性中。
• 返回字符串中遇到不等字符的位置。