Python，nltk是否將相同的列表值返回給兩個不同的列表？

Question

我想將文檔分成兩個列表，但是這兩個列表中的代碼給了我相同的數據。我定義了兩個單獨的字典，這些字典也是我在這裏使用的。

def feature_extractor(document): 
support_features = [] 
attack_features = [] 
for sentence in document: 
    if (word in sentence for word in supporting_ethos): 
     support_features.append(sentence) 
    if (word in sentence for word in attacking_ethos): 
     attack_features.append(sentence) 
return(attack_features , support_features) 

Answer 1

(.. for .. in ...)是generator expression。

>>> (x for x in [1,2]) 
<generator object <genexpr> at 0x0000000002A1B828> 

當它用作謂詞時，它總是被視爲真相。

>>> bool(_) 
True 

所以兩個表達式(word in sentence for word in supporting_ethos)和​​被評估爲真。

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您的意思是使用any來生成表達式嗎？

if any(word in sentence for word in supporting_ethos): 
    ...