2017-09-18 238 views
2

我在嵌套字典中分配困難。我有一個嵌套的詞典,有兩個學校,三個老師和四個學生。這僅僅是一個玩具的例子,所以我不在乎每個學校的學生和老師都是一樣的。但是,我希望每個等級都不同。但是,根據下面的代碼,所有班級和所有學校的所有學生的成績與最後輸入的學校/班級相同。嵌套字典分配錯誤 - 混淆可變字典

schools = ['School A', 'School B'] 
teachers = ['mr. smith', 'ms. jones', 'mr. kronk'] 
students = ['Adam', 'Nick', 'Jeff', 'Dave'] 
grade_dict ={} 
for i in students: 
    grade_dict[i] = '' 
    for j in teachers: 
     teachers_dict[j] = grade_dict 
     for k in schools: 
      school_dict[k] = teachers_dict 
for k in schools: 
    for j in teachers: 
     for i in students: 
      a = [randint(70, 100), randint(70, 100), randint(70, 100)] 
      school_dict[k][j][i] = a 

這就是我想要的數據看起來像:

School A mr. smith Adam [71, 72, 82] 
School A mr. smith Nick [86, 80, 96] 
School A mr. smith Jeff [77, 70, 83] 
School A mr. smith Dave [79, 83, 98] 
School A ms. jones Adam [70, 98, 87] 
School A ms. jones Nick [80, 94, 76] 
School A ms. jones Jeff [79, 82, 93] 
School A ms. jones Dave [90, 97, 85] 
School A mr. kronk Adam [93, 75, 95] 
School A mr. kronk Nick [80, 82, 72] 
School A mr. kronk Jeff [75, 72, 89] 
School A mr. kronk Dave [86, 92, 98] 
School B mr. smith Adam [89, 77, 84] 
School B mr. smith Nick [93, 71, 74] 
School B mr. smith Jeff [78, 83, 83] 
School B mr. smith Dave [72, 83, 70] 
School B ms. jones Adam [82, 100, 78] 
School B ms. jones Nick [80, 89, 100] 
School B ms. jones Jeff [91, 81, 77] 
School B ms. jones Dave [86, 86, 74] 
School B mr. kronk Adam [82, 73, 100] 
School B mr. kronk Nick [81, 71, 74] 
School B mr. kronk Jeff [92, 100, 90] 
School B mr. kronk Dave [86, 97, 85] 

這不幸的是,相應的字典的樣子:

{'School A': {'mr. kronk': {'Adam': [86, 89, 94], 
    'Dave': [74, 85, 86], 
    'Jeff': [79, 94, 70], 
    'Nick': [90, 80, 97]}, 
    'mr. smith': {'Adam': [86, 89, 94], 
    'Dave': [74, 85, 86], 
    'Jeff': [79, 94, 70], 
    'Nick': [90, 80, 97]}, 
    'ms. jones': {'Adam': [86, 89, 94], 
    'Dave': [74, 85, 86], 
    'Jeff': [79, 94, 70], 
    'Nick': [90, 80, 97]}}, 
'School B': {'mr. kronk': {'Adam': [86, 89, 94], 
    'Dave': [74, 85, 86], 
    'Jeff': [79, 94, 70], 
    'Nick': [90, 80, 97]}, 
    'mr. smith': {'Adam': [86, 89, 94], 
    'Dave': [74, 85, 86], 
    'Jeff': [79, 94, 70], 
    'Nick': [90, 80, 97]}, 
    'ms. jones': {'Adam': [86, 89, 94], 
    'Dave': [74, 85, 86], 
    'Jeff': [79, 94, 70], 
    'Nick': [90, 80, 97]}}} 

似乎有類似的問題在stackoverflow,但他們不能幫助我解決這裏發生的事情。謝謝。

回答

1

您可以使用字典解析:

from random import randint 
schools = ['School A', 'School B'] 
teachers = ['mr. smith', 'ms. jones', 'mr. kronk'] 
students = ['Adam', 'Nick', 'Jeff', 'Dave'] 

final_dict = {school:{teacher:{student:[randint(70, 100), randint(70, 100), randint(70, 100)] for student in students} for teacher in teachers} for school in schools} 

輸出:

{'School A': {'mr. smith': {'Nick': [75, 81, 86], 'Dave': [85, 88, 84], 'Adam': [78, 95, 99], 'Jeff': [74, 95, 81]}, 'ms. jones': {'Nick': [76, 86, 92], 'Dave': [92, 100, 95], 'Adam': [98, 99, 90], 'Jeff': [74, 100, 95]}, 'mr. kronk': {'Nick': [84, 97, 79], 'Dave': [93, 91, 89], 'Adam': [83, 98, 79], 'Jeff': [89, 83, 99]}}, 'School B': {'mr. smith': {'Nick': [70, 78, 89], 'Dave': [81, 95, 92], 'Adam': [95, 100, 91], 'Jeff': [91, 83, 82]}, 'ms. jones': {'Nick': [94, 85, 75], 'Dave': [99, 77, 94], 'Adam': [79, 97, 92], 'Jeff': [91, 84, 79]}, 'mr. kronk': {'Nick': [81, 90, 86], 'Dave': [72, 95, 82], 'Adam': [80, 73, 77], 'Jeff': [88, 88, 95]}}} 
+0

硬編碼像這樣最終的字典是不是最好的。 –

+0

這是初始化字典的一種很酷的方式(謝謝!),但並不完全解決在嵌套字典中最低級別創建唯一值的問題。 –

+0

@GeoffPerrin我很抱歉沒有意識到你想讓學生成績隨機化!請參閱我最近的編輯。 – Ajax1234

1

你是(重新)在整個字典中使用相同的grade_dict對象。 每次迭代創建單獨的對象。此外,你並不需要在每個鍵初始化值:

for i in students: 
    for j in teachers: 
     teachers_dict[j] = {} 
     for k in schools: 
      school_dict[k] = teachers_dict 

OTOH,你應該避免使用嵌套collections.defaultdict聲明school_dict預分配與值/類型的字典進行

from collections import defaultdict 

school_dict = defaultdict(lambda: school_dict) # dict nesting is recursive 

for k in schools: 
    for j in teachers: 
     for i in students: 
      school_dict[k][j][i] = [randint(70, 100), randint(70, 100), randint(70, 100)]