mysql的2臺，獲得從2個表

Question

導致我有2個表

1表=文件

 code      | title 

luLidwhSl8hmN0T6RsLaDmxAB09UZcX |這是的RAR標題

4Xwvm1C3yTQJK7CnmxorUDI7sNSvcBK |這是JPG標題

...

2表=匹配

 page_name        | hits 

的download.php碼= luLidwhSl8hmN0T6RsLaDmxAB09UZcX | 102

的download.php碼= 4Xwvm1C3yTQJK7CnmxorUDI7sNSvcBK | 87

...

我的查詢是：？？

  include('db.inc.php'); 
      $query = mysql_query("SELECT t1.code, t1.title, RIGHT(t2.page_name, 31) as t2.page_name, t2.hits FROM files t1 INNER JOIN hits t2 ON t1.code= RIGHT(t2.page_name, 31) as t2.page_name ORDER by t2.hits DESC LIMIT 1, 7"); 

      while ($result = mysql_fetch_assoc($query)) { 
       echo ' <div id="linkstyle"><strong><a href="http://localhost/edu/filesupload/download.php?code='. $result['t1.code'] . ' ">' , $result['t1.title'] , '</a></strong><br></div>'; 
       } 

我收到此錯誤

Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\Edu\filesupload\index.php on line 104 

問題在哪裏？

Answer 1

更改此：

$query = mysql_query("SELECT t1.code, t1.title, RIGHT(t2.page_name, 31) as t2.page_name, t2.hits FROM files t1 INNER JOIN hits t2 ON t1.code= RIGHT(t2.page_name, 31) as t2.page_name ORDER by t2.hits DESC LIMIT 1, 7");

要這樣：

$query = mysql_query("SELECT t1.code, t1.title, RIGHT(t2.page_name, 31) as t2.page_name, t2.hits FROM files t1 INNER JOIN hits t2 ON t1.code= RIGHT(t2.page_name, 31) as t2.page_name ORDER by t2.hits DESC LIMIT 1, 7") or die(mysql_error());

那麼就應該告訴你的是什麼錯誤，因爲如果這是罰款，但不會回到假。

Answer 2

嘗試與此查詢：

SELECT t1.code, t1.title, RIGHT(t2.page_name, 31) as page_name, t2.hits FROM files t1 INNER JOIN hits t2 ON t1.code= RIGHT(t2.page_name, 31) ORDER by t2.hits DESC LIMIT 1, 7