PHP get方法AJAX URL讀

Question

我有這樣的URL

site.com/#request/values-1

site.com/#request/values-2

我如何取這個網址？與PHP你認爲這是關於什麼？

$request = ? 

Answer 1

編輯︰你需要使用JavaScript來實現。

<script language = "javascript"> 

var query = location.href.split('#'); 

var anchorValueSplit = query[1].split("/"); 

var anchorValue = anchorValueSplit[1]; 

alert(anchorValue); 

</script> 

編輯：另一個解決方案

<script language = "javascript"> 

if(location.href.indexOf("#") > 0) { 

    location.href = location.href.replace("#","?"); 

} 

</script> 
<?php 

$param = array_keys($_GET); 
$param = $param[0]; 

$breakParam = explode("/",$param); 

echo $request = $breakParam[1]; 


?>