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我試圖構建zguide C++示例,但編譯失敗。以下是錯誤輸出中:zGuide for zeroMQ編譯失敗
asyncsrv.cpp: In member function ‘void client_task::start()’:
asyncsrv.cpp:37:70: error: cannot convert ‘zmq::socket_t’ to ‘void*’ in initialization zmq::pollitem_t items[] = {{client_socket_, 0, ZMQ_POLLIN, 0}};
asyncsrv.cpp: In member function ‘void server_task::run()’: asyncsrv.cpp:140:52: error: cannot convert ‘zmq::socket_t’ to ‘void*’ for argument ‘1’ to ‘void zmq::proxy(void*, void*, void*)’ zmq::proxy(frontend_, backend_, nullptr);
聽起來可能是您安裝的ZMQ和您試圖運行的示例代碼之間的版本不兼容...您介意給出您的ZMQ版本和示例代碼的鏈接? – Jason
zmqversion是4.1.3,zGuide具有最新的標籤v2.2-1024-g40230a3並提交sha1 40230a37eb45d8564733bedc08c333190387df3d。 C樣本構建得很好。 –