django中的pre_delete信號中的當前用戶

Question

是否有可能在連接到pre_delete信號的回調中獲得登錄的django用戶（即調用模型的刪除方法）？

Answer 1

pre_delete信號沒有通過請求實例，但是您可以添加一個裝飾器，添加它並在視圖上使用該裝飾器，這會刪除指定的模型。

假設這是回調函數：這是在裝飾添加

def pre_delete_cb(sender, instance, using, **kwargs): 
    pass 

：

from django.db.models.signals import pre_delete 
from functools import wraps 
from django.utils.decorators import available_attrs 

def pre_delete_dec(cb, sender): 
    def decorator(view_func): 
     @wraps(view_func, assigned=available_attrs(view_func)) 
     def _wrapped_view(request, *args, **kwargs): 
      cb.request = request # here we add the request to the callback function 
      pre_delete.connect(cb, sender=sender) # and connecting the real pre_delete to the callback 
      return view_func(request, *args, **kwargs) 
     return _wrapped_view 
    return decorator 

並使用在你打電話的方式視圖的裝飾 - 而不是pre_delete.connect(pre_delete_cb, MyModel)，使用：

@pre_delete_dec(pre_delete_cb, MyModel) 
def myview(request): 

然後在回調中，您將有權訪問t Ø請求爲：

def pre_delete_cb(sender, instance, using, **kwargs): 
    current_user = pre_delete_cb.request.user 

您可以在全球範圍添加此，不只是每個視圖 - 使用中間件：

from django.db.models.signals import pre_delete 

def pre_delete_cb(sender, instance, using, **kwargs): 
    current_user = pre_delete_cb.request.user 

class PreDeleteMiddleware(object): 
    def process_view(self, request, view_func, view_args, view_kwargs): 
     pre_delete_cb.request = request 
     from myapp.models import MyModel 
     pre_delete.connect(pre_delete_cb, sender=MyModel)