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我需要[Contribution]的查詢。我用這個查詢:SQL Server中的多個聚合函數
with ttt as
(
select
(DYG.U_StyleId)[DYG Style]
,Max(O1.CardCode) [Party Group Code],
MAX(O1.CardName) [Party Group Name]
,MAX(OR1.DocDate) [Date]
,sum(CONVERT(NUMERIC(15,2),(RDR1.PriceBefDi*RDR1.Quantity))) [JobAmount]
,CONVERT(NUMERIC(15,2),SUM(RDR1.Quantity)) [Mtr]
,CONVERT(NUMERIC(15,2),SUM(RDR1.U_Pcs))[Pcs]
,(select sum(RDR1.PriceBefDi*RDR1.Quantity) from RDR1) tqty
from
ORDR OR1
left join RDR1 on RDR1.DocEntry = OR1.DocEntry
left join OITM on RDR1.ItemCode = oitm.ItemCode
LEFT JOIN OCRD ON OCRD.CardCode = OR1.CardCode
LEFT JOIN OCRG ON OCRG.GroupCode = OCRD.GroupCode
LEFT JOIN OCRD O1 ON O1.U_BCode = OCRD.U_GrpCod
LEFT JOIN
(SELECT U_StyleId FROM RDR1 WHERE U_StyleId in
('BLOOM','BLOOMING','DYD','DYD-R','DYED','Ex.CLR.','RAINBOW'))
DYG ON DYG.U_StyleId = RDR1.U_StyleId
group by
DYG.U_StyleId
)
select
Style, [Party Group Code],
[Party Group Name], JobAmount,
(sum(JobAmount)/tqty * 100) [Contribution],
[Date], [Pcs]
from
ttt
group by
Style
我需要最後jobamount的總和除以上面的tqty。 但它顯示此錯誤。
'列'ttt.Party組代碼'在選擇列表中無效,因爲它不包含在聚合函數或GROUP BY子句中。'
請用我的查詢來獲得合適的[貢獻]金額。
請檢查我的版本有問題 – Bha15