如何在Python中僅以小時，分鐘和秒來打印差異（如td = 33:23:21）？

Question

import Datetime 

str1 = "2017-05-01 18:23:22" #String one of time 
str2 = "2017-05-02 23:16:22" #String two of time 

#Turning it to datetime objects 

T1 = datetime.datetime.strptime(str1, "%Y-%m-%d %H:%M:%S") 
T2 = datetime.datetime.strptime(str2, "%Y-%m-%d %H:%M:%S") 

DIFF = T2 -T1 
print DIFF 

輸出如下：1天，4點53分○○秒 所需outout：28:53:00

Answer 1

這裏亞去，將它添加到你的代碼的底部打印出所需的格式：

days = DIFF.days 
hours, remainder = divmod(DIFF.seconds, 3600) 
minutes, seconds = divmod(remainder, 60) 

print str(days * 24 + hours) + ":" + str("%02d" % minutes) + ":" + str("%02d" % seconds)