計算在php中的時間差異

Question

我想計算我的數據庫中當前時間和時間的不同時間。數據庫中的時間格式爲日期時間("Y-m-d H:i:s")。這是我的代碼。我是新來的PHP，如果我寫了一個愚蠢的代碼，我很抱歉。

<?php 
try { 
    $dbh = new PDO("mysql:host=$hostname;dbname=", $username, $password); 


    $sql = "select * from time"; 
    echo "<table>"; 
    echo "<tr><th>ID</th><th>Name</th><th>Time</th></tr>"; 
    foreach ($dbh->query($sql) as $row) 
     { 
     $id=$row['id']; 
     echo "<tr>"; 
     echo "<td>" . $row['id'] ."</td>"; 
     echo "<td>" . $row['name'] . "</td>"; 
     echo "<td>" . $row['time'] . "</td>"; 

     echo "</tr>"; 
     } 
    echo "</table>"; 
    $today=date("Y-m-d H:i:s"); 
    $timeleft=($row['time']-$today); 
    echo $today; 
    echo 'Time left: '.$timeleft; 
     $dbh = null; 
    } 
    catch(PDOException $e) { echo $e->getMessage(); } 

?> 

Answer 1

<?php 
$datetime1 = new DateTime('2009-10-11'); 
$datetime2 = new DateTime('2009-10-13'); 
$interval = $datetime1->diff($datetime2); 
echo $interval->format('%R%a days'); 
?> 

Answer 2

如何在查詢計算？

$sql = "select *, (t.time - NOW()) AS 'difference' from time t";

然後你只需要回聲回聲'Time left: ' . $row['difference'];