我想替換多個匹配項中特定單詞的匹配項並僅保留最後一個。替換字符串中的多個匹配項
"How about a how about b how about c" to ==>
"a b How about c"
我用與string.replace全部更換出現時但我還是想最後one.sorry如果是天真
我想替換多個匹配項中特定單詞的匹配項並僅保留最後一個。替換字符串中的多個匹配項
"How about a how about b how about c" to ==>
"a b How about c"
我用與string.replace全部更換出現時但我還是想最後one.sorry如果是天真
的一種方法是使用某種類型的循環檢查,看看是否有任何事..
function allButLast(haystack, needle, replacer, ignoreCase) {
var n0, n1, n2;
needle = new RegExp(needle, ignoreCase ? 'i' : '');
replacer = replacer || '';
n0 = n1 = n2 = haystack;
do {
n2 = n1; n1 = n0;
n0 = n0.replace(needle, replacer);
} while (n0 !== n1);
return n2;
}
allButLast("How about a how about b how about c", "how about ", '', 1);
// "a b how about c"
謝謝!很棒。深深地感謝 –
@JackDre在_stackoverflow_上有一些有用的東西時,不要忘記註冊它。然後,如果答案解決了您的問題,請不要忘記將其標記爲解決方案。 –
我試過了,我現在只有14人,現在只有一人downvoted :)一旦我把它拿回來,我會upvote。 –
不管語言,沒有內置的方法來做到這一點。 你可以做什麼是一樣的東西(可能需要調試)
string customReplace(string original, string replaceThis, string withThis)
{
int last = original.lastIndexOf(replaceThis);
int index = s.indexOf(replaceThis);
while(index>=0 && index < last)
{
original = original.left(index)+ original.right(index+replaceThis.length);
last = original.lastIndexOf(replaceThis); // gotta do this since you changed the string
index = s.indexOf(replaceThis);
}
return original; // same name, different contents. In C# is valid.
}
謝謝。讚賞。 –
稍微不同的方法,同時支持正則表達式和普通字符串針:
var replaceAllBarLast = function(str, needle, replacement){
var out = '', last = { i:0, m: null }, res = -1;
/// RegExp support
if (needle.exec) {
if (!needle.global) throw new Error('RegExp must be global');
while((res = needle.exec(str)) !== null) {
(last.m) && (last.i += res[0].length, out += replacement);
out += str.substring(last.i, res.index);
last.i = res.index;
last.m = res[0];
}
}
/// Normal string support -- case sensitive
else {
while((res = str.indexOf(needle, res+1)) !== -1) {
(last.m) && (last.i += needle.length, out += replacement);
out += str.substring(last.i, res);
last.i = res;
last.m = needle;
}
}
return out + str.substring(last.i);
}
var str = replaceAllBarLast(
"How about a how about b how about c",
/how about\s*/gi,
''
);
console.log(str);
你能找到的最後一個表達式的索引,然後將它移動到它自己的字符串中,然後執行替換,然後將字符串重新排列在一起。 – ermagana