Question

這裏是我的代碼 - >進步，report.php 數據類型LONGBLOB，API是FPDF

$res=mysqli_query($conn,"SELECT school_logo FROM dsms_school_img"); 
while($row=mysqli_fetch_array($res)) 
{ 
    $logo = '<img src="data:image/jpeg;base64,'.base64_encode($row['school_logo']).'"/>'; 
} 

當我把這個$logo在$pdf->Image($logo,10,10,188);它表明這個錯誤：

Fatal error: Uncaught Exception: FPDF error: Image file has no extension and no type was specified: <img src="data:image/jpeg;base64,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 in C:\xampp\htdocs\dignitysmslatest\admin\Module\manage\pdf\fpdf.php on line 271 

Answer 1

內存映像支持

信息

作者：奧利維爾 許可證：FPDF 描述

此腳本允許顯示加載到內存中的圖像，而不需要臨時文件。主要有兩種用途：

• 當圖像被從數據庫
• 裝載當用GD

創建的圖像加載到一個字符串的圖像：

MemImage（字符串數據[，float x [，float y [，float w [，float h [，mixed link]]]]]）

對於GD圖像：

GDImage（資源im [，float x [，float y [，float w [，float h [，mixed link]]]]]）

其中im是GD標識符。如果你使用JpGraph，你可以通過調用$ graph-> Stroke（_IMG_HANDLER）來獲取它。

$query = "SELECT school_logo FROM dsms_school_img"; 
    $result = mysqli_query($query); 
    $row = mysql_fetch_assoc($result); 
    $image = $row['imageField']; 

    $pdf->MemImage($image, 50, 30);