具有多個值的動態下拉框的預選值

Question

我試圖在多個下拉列表中的編輯頁面上預先選擇值，因此一旦用戶單擊編輯，就可以看到已插入的值。值被保存爲逗號分隔在MySQL中像「1,2,3,4,5」

嘗試此解決方案，但不起作用:(是否有任何方式，這些值將被預選？請幫助

<select name="w_owning_branches[]" size="10" id="w_owning_branches" multiple="multiple" required> 
<option value="" class="dropdown-option"> Select Owning Branch </option> 
<?php do { 

$value = $row_branches['branch_id']; 
$name = $row_branches['name']; 
$selected = '1,2,3,4,5,6'; 

echo "<option value='$value'".(($selected == '$value') ? " selected='selected'":"").">$name</option>"; 


} while ($row_branches = mysql_fetch_assoc($branches)); ?> 
</select> 

Answer 1

嘗試：

<select name="w_owning_branches[]" size="10" id="w_owning_branches" multiple="multiple" required> 
<option value="" class="dropdown-option"> Select Owning Branch </option> 
<?php do { 

$value = $row_branches['branch_id']; 
$name = $row_branches['name']; 
$selected = '1,2,3,4,5,6'; 
$selected_values = explode(",",$selected); 

echo "<option value='$value'".((in_array($value,$selected_values)) ? " selected='selected'":"").">$name</option>"; 


} while ($row_branches = mysql_fetch_assoc($branches)); ?> 
</select> 

Answer 2

你可以使用這樣的事情：

$selected = '1,2,3,4,5,6'; 
$selectedArr = explode(",", $selected); 
echo "<option value='$value'".((in_array($value, $selectedArr))?" SELECTED ":"").">$name</option>"; 

Answer 3

如果我理解正確的話，T如果所選值存儲在逗號分隔的字符串中，並且數字是之前選擇的值。

在這種情況下，答案很簡單：

<select name="w_owning_branches[]" size="10" id="w_owning_branches" multiple="multiple" required> 
<option value="" class="dropdown-option"> Select Owning Branch </option> 
<?php do { 

$value = $row_branches['branch_id']; 
$name = $row_branches['name']; 
$selected = '1,2,3,4,5,6'; 

echo "<option value='$value'".(in_array($value, explode(",",$selected)) ? " selected='selected'":"").">$name</option>"; 


} while ($row_branches = mysql_fetch_assoc($branches)); ?> 
</select>