將javascript數組鍵合併到內部數組中？

Question

我有由PHP生成一個JavaScript陣列，使這個：

var sections = [ 
    section1 => 
    [name => anthony, email => test@test.com], 
    section1 => 
    [name => anthony, email => test@test.com], 
    section1 => 
    [name => anthony, email => test@test.com], 
    section2 => 
    [name => anthony, email => test@test.com], 
    section2 => 
    [name => anthony, email => test@test.com] 
] 

什麼使它的最好辦法：

var sections = [ 
    section1 => 
    [name => anthony, email => test@test.com], 
    [name => anthony, email => test@test.com], 
    [name => anthony, email => test@test.com], 
    section2 => 
    [name => anthony, email => test@test.com], 
    [name => anthony, email => test@test.com] 
] 

合併所有像鑰匙，並把所有的內部數組到同一個池。

因此，我可以循環每個部分作爲「部分」，而不是同一部分的部分。

Answer 1

你發佈的內容不是有效的JavaScript，所以你不明白你在找什麼結構。另外，您不應該讓PHP輸出有問題/重複的JavaScript，然後嘗試在稍後使用JavaScript進行清理，應該修改PHP以產生良好的JavaScript。將輸出存儲在PHP數組中不應該很難，而不是隻輸出它，然後只輸出唯一的元素（節）到JavaScript

這就是說，有一個簡單的修改您目前的輸出使其有效的JavaScript。我繼續追加"1"，"2"等的字符串末尾，使其明顯會發生什麼情況重複：

var sections = { 
    section1 : 
    {name : "anthony1", email : "test@test.com1"}, 
    section1 : 
    {name : "anthony2", email : "test@test.com2"}, 
    section1 : 
    {name : "anthony3", email : "test@test.com3"}, 
    section2 : 
    {name : "anthony4", email : "test@test.com4"}, 
    section2 : 
    {name : "anthony5", email : "test@test.com5"}, 
}; 

console.log(sections.section1.name, sections.section1.email); // "anthony3" "test@test.com3" 
console.log(sections.section2.name, sections.section2.email); // "anthony5" "test@test.com5" 

沒有附加"1"，"2"等：

var sections = { 
    section1 : 
    {name : "anthony", email : "test@test.com"}, 
    section1 : 
    {name : "anthony", email : "test@test.com"}, 
    section1 : 
    {name : "anthony", email : "test@test.com"}, 
    section2 : 
    {name : "anthony", email : "test@test.com"}, 
    section2 : 
    {name : "anthony", email : "test@test.com"}, 
}; 

console.log(sections.section1.name, sections.section1.email); // "anthony" "test@test.com" 
console.log(sections.section2.name, sections.section2.email); // "anthony" "test@test.com"