2012-03-05 77 views

回答

0

嘗試......它會爲我工作..

EditText status="test Message from Android "; 
twitter = new Twitter(username, password); 
String token = "Your Token ID"; 
String secret = "Your Secret Code"; 
twitter4j.Twitter twitter = new TwitterFactory().getInstance(); 
AccessToken a = new AccessToken(token, secret); 
twitter.setOAuthConsumer(CONSUMER_KEY, CONSUMER_SECRET); 
twitter.setOAuthAccessToken(a); 
try { 
     twitter.updateStatus(status.getText().toString()); 
} catch (TwitterException e) { 
// TODO Auto-generated catch block 
e.printStackTrace(); 
} 
} 
+0

我沒有明白。你不是在使用twitter變量兩次嗎?它不會導致錯誤 – user1030768 2012-03-06 07:50:20