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我發現瞭如何發現如果數據庫使用此代碼存在：安裝腳本 - 如何檢查數據庫表是否已經存在？
if(mysql_select_db('db-name'))
return true;
但我想檢查數據庫中的表。這裏是代碼：
error_reporting(0);
session_start();
global $_ERROR;
$_ERROR = array();
$installed = false;
if($_POST)
{
$num = 0;
foreach($_POST as $key=>$value)
{
if(strlen(str_replace(" ","",$value))<=0 && $key!='db_pass')
{
$_ERROR[$key] = 'class="error"';
$num ++;
}
}
if($num>0)
{
$_ERROR['text'] = 'Please fill in all fields';
}
else
{
// Create Database
$con = mysql_connect($_POST['db_server'],$_POST['db_user'],$_POST['db_pass']);
if (!$con) {
$_ERROR['text'] = 'There was an error connecting to your database';
}
else
{
if(mysql_select_db($_POST['db_name'])){
}
$db = mysql_select_db($_POST['db_name'],$con);
if(!$db)
{
$_ERROR['text'] = 'Could not select database';
}
else
{
foreach($_POST as $key=>$value)
{
$_POST[$key] = mysql_real_escape_string($value,$con);
}
$sql = 'SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
CREATE TABLE `active_guests` (
`ip` varchar(15) collate latin1_general_ci NOT NULL,
`timestamp` int(11) unsigned NOT NULL,
PRIMARY KEY (`ip`)
);';
mysql_query($sql,$con) or die(mysql_error());
$sql = 'CREATE TABLE `active_users` (
`username` varchar(30) collate latin1_general_ci NOT NULL,
`timestamp` int(11) unsigned NOT NULL,
PRIMARY KEY (`username`)
);';
mysql_query($sql,$con) or die(mysql_error());
$sql = 'CREATE TABLE `banned_users` (
`username` varchar(30) collate latin1_general_ci NOT NULL,
`timestamp` int(11) unsigned NOT NULL,
PRIMARY KEY (`username`)
);';
mysql_query($sql,$con) or die(mysql_error());
$sql = "CREATE TABLE `forum` (
`postid` bigint(20) NOT NULL auto_increment,
`author` varchar(255) collate latin1_general_ci NOT NULL default '',
`title` varchar(255) collate latin1_general_ci NOT NULL default '',
`post` mediumtext collate latin1_general_ci NOT NULL,
`showtime` varchar(255) collate latin1_general_ci NOT NULL default '',
`realtime` bigint(20) NOT NULL default '0',
`lastposter` varchar(255) collate latin1_general_ci NOT NULL default '',
`numreplies` bigint(20) NOT NULL default '0',
`parentid` bigint(20) NOT NULL default '0',
`lastrepliedto` bigint(20) NOT NULL default '0',
`author_avatar` varchar(30) collate latin1_general_ci NOT NULL default 'default',
`type` varchar(2) collate latin1_general_ci NOT NULL default '1',
`stick` varchar(6) collate latin1_general_ci NOT NULL default '0',
`numtopics` bigint(20) NOT NULL default '0',
`cat` bigint(20) NOT NULL,
PRIMARY KEY (`postid`)
);";
mysql_query($sql,$con) or die(mysql_error());
$sql = "CREATE TABLE `messages` (
`id` int(11) NOT NULL auto_increment,
`reciever` varchar(25) NOT NULL default '',
`sender` varchar(25) NOT NULL default '',
`subject` text NOT NULL,
`message` longtext NOT NULL,
`recieved` enum('1','0') default '0',
PRIMARY KEY (`id`)
);";
mysql_query($sql,$con) or die(mysql_error());
$sql = "CREATE TABLE `news` (
`id` int(11) NOT NULL auto_increment,
`titre` varchar(255) collate latin1_general_ci NOT NULL,
`contenu` text collate latin1_general_ci NOT NULL,
`timestamp` bigint(20) NOT NULL default '0',
PRIMARY KEY (`id`)
);";
mysql_query($sql,$con) or die(mysql_error());
$sql = "CREATE TABLE `settings` (
`id` int(11) NOT NULL auto_increment,
`name` varchar(25) NOT NULL default '',
`value` varchar(20) NOT NULL,
PRIMARY KEY (`id`)
);";
mysql_query($sql,$con) or die(mysql_error());
$sql = "CREATE TABLE `users` (
`username` varchar(30) collate latin1_general_ci NOT NULL,
`password` varchar(32) collate latin1_general_ci default NULL,
`userid` varchar(32) collate latin1_general_ci default NULL,
`userlevel` tinyint(1) unsigned NOT NULL,
`email` varchar(50) collate latin1_general_ci default NULL,
`timestamp` int(11) unsigned NOT NULL,
`web` varchar(90) collate latin1_general_ci default 'Sorry, i dont have a website.',
`country` varchar(90) collate latin1_general_ci NOT NULL,
`avatar` varchar(30) collate latin1_general_ci NOT NULL default 'default',
`status` varchar(50) collate latin1_general_ci NOT NULL,
`pm_count` int(11) NOT NULL default '0',
`statusmessage` mediumtext COLLATE latin1_general_ci NOT NULL,
PRIMARY KEY (`username`)
);";
mysql_query($sql,$con) or die(mysql_error());
$pass = md5($_POST['password']);
$sql = "INSERT INTO `users` VALUES ('$_POST[name]', '$pass', '0', '9', '$_POST[email]', '', '', '', 'default', '', '0', 'Hello world!')";
mysql_query($sql,$con) or die(mysql_error());
$sql = "INSERT INTO `settings` VALUES (1, 'update', '0')";
mysql_query($sql,$con) or die(mysql_error());
$sql = "INSERT INTO `settings` VALUES (2, 'title', '$_POST[sitename]')";
mysql_query($sql,$con) or die(mysql_error());
$sql = "INSERT INTO `settings` VALUES (3, 'frontnews', '0')";
mysql_query($sql,$con) or die(mysql_error());
$sql = "INSERT INTO `settings` VALUES (4, 'headercolor', '#7387a7')";
mysql_query($sql,$con) or die(mysql_error());
$sql = "INSERT INTO `settings` VALUES (5, 'numpms', '50')";
mysql_query($sql,$con) or die(mysql_error());
$file = fopen("db.php","r");
$data = fread($file, 500000);
fclose($file);
$data = str_replace('define("INSTALLED",FALSE);','define("INSTALLED",TRUE);',$data);
$data = str_replace('HOST',$_POST['db_server'],$data);
$data = str_replace('USER_',$_POST['db_user'],$data);
$data = str_replace('PASSWORD',$_POST['db_pass'],$data);
$data = str_replace('DBNAME',$_POST['db_name'],$data);
$data = str_replace('EMAIL_NAME',$_POST['email_name'],$data);
$data = str_replace('_EMAIL',$_POST['email'],$data);
$file = fopen("db.php","w");
fwrite($file, $data, 500000);
fclose($file);
header("Location: ../index.php");
}
}
}
}
$_POST['siteurl'] = str_replace("/includes/install.php","","http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']);
?>
其餘的是html，所以沒用。基本上，如果我安裝後再次運行這個安裝腳本，它會給我一個錯誤，說明表「活動客戶」已經存在。 （它的第一個表創建，所以它總是這一個顯示。）
我想添加一個表的檢查告訴腳本：表已經存在，所以不要修改它們，只是創建數據庫.php文件而不接觸數據庫。
我可以在插入數據的地方使用它嗎？ 編輯：我發現INSERT IGNORE INTO查詢，應該工作！ – blackjak231 2010-07-31 15:14:50