PHP MySql PDO多重插入不起作用

Question

我有一個多重插入查詢的代碼（我必須將數據從數據庫傳輸到另一個並進行一些更新，所以我想使用一個代碼可以自動完成所有這些）

$query = "select * from pubblicate order by idPubblicate asc"; 

$dbh = newPdo2(); 
$dbh->exec("set names utf8"); 

$sth = $dbh->prepare($query); 
$sth->execute(); 

$count = 0; 
$query2 = "insert into published_offer 
      (codice_onshop,nome,inbreve,anteprima, 
      galleria1,galleria2,galleria3,galleria4,prezzo, 
      tp_prezzo,bonus_usabile,proposta,condizioni, 
      prenotare,categoria,description,keywords, 
      valido_da,valido_a) "; 

while($offerta = $sth->fetch(PDO::FETCH_ASSOC)) { 
    $array[$count]['id'] = $offerta['idPubblicate']; 
    $array[$count]['co'] = $offerta['codiceOfferta']; 
    $array[$count]['no'] = $offerta['nomeOfferta']; 
    $array[$count]['ib'] = $offerta['inBreve']; 
    $array[$count]['ke'] = $offerta['keywords']; 
    $array[$count]['de'] = $offerta['description']; 
    $array[$count]['pr'] = $pfferta['prezzo']; 
    $array[$count]['pe'] = $offerta['persona']; 
    $array[$count]['da'] = $offerta['daTimer']; 
    $array[$count]['a'] = $offerta['aTimer']; 
    $array[$count]['an'] = $offerta['anteprima']; 
    $array[$count]['g1'] = $offerta['galleria1']; 
    $array[$count]['g2'] = $offerta['galleria2']; 
    $array[$count]['g3'] = $offerta['galleria3']; 
    $array[$count]['g4'] = $offerta['galleria4']; 
    $array[$count]['pro'] = $offerta['proposta']; 
    $array[$count]['con'] = $offerta['condizioni']; 
    $array[$count]['pre'] = $offerta['prenotare']; 
    $array[$count]['bo'] = 999; 

    if($offerta['italia']=="Sì")  $array[$count]['ca'] = "ita"; 
    else if($offerta['europa']=="Sì") $array[$count]['ca'] = "eur"; 
    else if($offerta['mondo']=="Sì") $array[$count]['ca'] = "mon"; 
    $count++; 
} 

$query2 .= "values (:co,:no,:ib,:an,:g1,:g2, 
        :g3,:g4,:pr,:pe,:bo,:pro,:con, 
        :pre,:ca,:de,:ke,:da,:a)"; 

$dbh = newPdo(); 
$dbh->exec("set names utf8"); 
$sth = $dbh->prepare($query2); 

$i=0; 
echo $array[0]['no'] . " " . count($array) . " " . $array[125]['no'] . "<br>" . $query2 . "<br>"; 

while($i<count($array)) { 
    $sth->bindParam(":co", $array[$i]['co']); 
    $sth->bindParam(":no", $array[$i]['no']); 
    $sth->bindParam(":ib", $array[$i]['ib']); 
    $sth->bindParam(":an", $array[$i]['an']); 
    $sth->bindParam(":g1", $array[$i]['g1']); 
    $sth->bindParam(":g2", $array[$i]['g2']); 
    $sth->bindParam(":g3", $array[$i]['g3']); 
    $sth->bindParam(":g4", $array[$i]['g4']); 
    $sth->bindParam(":pr", $array[$i]['pr']); 
    $sth->bindParam(":pe", $array[$i]['pe']); 
    $sth->bindParam(":bo", $array[$i]['bo']); 
    $sth->bindParam(":pro",$array[$i]['pro']); 
    $sth->bindParam(":con",$array[$i]['con']); 
    $sth->bindParam(":pre",$array[$i]['pre']); 
    $sth->bindParam(":ca", $array[$i]['ca']); 
    $sth->bindParam(":de", $array[$i]['de']); 
    $sth->bindParam(":ke", $array[$i]['ke']); 
    $sth->bindParam(":da", $array[$i]['da']); 
    $sth->bindParam(":a", $array[$i]['a']); 

    $sth->execute(); 
    $i++; 
} 

但這代碼不起作用。我也嘗試使用try-catch(PDOException)作爲$sth->execute()，但它沒有顯示任何東西。

爲什麼？

誰說「這個問題是一個重複」並沒有真正閱讀問題。逸岸的錯誤是一個錯誤的字符：$array[$count]['pr'] = $pfferta['prezzo']將一直$array[$count]['pr'] = $offerta['prezzo']，所以我無法找到另一個問題的答案。

Answer 1

嘗試加入一些簡單的檢查，事情其實像這樣工作

$res = $sth->execute(); 
if (! $res) { 
    echo sprintf('ERROR: %d - %s', $sth->errorCode(), $sth->errorInfo()); 
}