public function addSpouse($name = ($this->data['gender'] == MALE && empty($name)) ? 'Wife' : 'Husband', $suggest = false)
PHP默認值以下爲上述行:
syntax error, unexpected '$this' (T_VARIABLE)
$this
不允許在函數參數?
編輯:功能是一類
public function addSpouse($name = ($this->data['gender'] == MALE && empty($name)) ? 'Wife' : 'Husband', $suggest = false)
PHP默認值以下爲上述行:
syntax error, unexpected '$this' (T_VARIABLE)
$this
不允許在函數參數?
編輯:功能是一類
內它是從內部本身引用類的一個實例的方式,相同的許多其它面向對象的語言。 $this
指當前類的實例
參考PHP docs
The pseudo-variable $this is available when a method is called from within an object context. $this is a reference to the calling object (usually the object to which the method belongs, but possibly another object, if the method is called statically from the context of a secondary object).
不能使用一個變量($這個 - >數據或任何變量)作爲默認的參數值。 默認的功能參數值必須是常數。
public function addSpouse($name = 'Wife')
是正確的,但不能:
public function addSpouse($name = $data)
當然,不是。 '$ this'是對類實例的引用。如果沒有對象,你打算提及什麼? – abcdn
可能重複的[解析錯誤:語法錯誤,意外(T \ _VARIABLE)](http://stackoverflow.com/questions/28952930/parse-error-syntax-error-unexpected-t-variable) – Anil
addSpouse是在一個類。 – Piyush