Django Views中的嵌套SQL查詢

所以我搜索了這個到目前爲止還找不到任何答案。我在那裏的時候，我已經把在數據庫：Django Views中的嵌套SQL查詢

SELECT event_name, team_number 
FROM teams_by_event 
WHERE team_number IN (SELECT team_number 
        FROM teams_by_event 
        WHERE event_name = '[user inputs event name]' 
        ) ORDER BY team_number;

它給了我正是我要找的回報。我的問題是，我想不出在Django視圖中執行此操作的方法，以及我嘗試過的方法，只是在Django中使用原始SQL也無法正常工作，但我得到一個語法錯誤，指出上一個括號SQL查詢無效。

views.py：

def teams_by_event(request, shorthand): 
    code = TeamsByEvent.objects.filter(shorthand=shorthand) 
    for event in TeamsByEvent.objects.raw('SELECT event_name, team_number \ 
           FROM teams_by_event \ 
           WHERE team_number IN \ 
           (SELECT team_number \ 
           FROM teams_by_event) \ 
           WHERE shorthand= % s', [code]) 
    print (event.team_number, event.event_name) 
    return render(request, 'event-info.html', {'info': info})

models.py

class TeamsByEvent(models.Model): 
    team_number = models.IntegerField() 
    event_name = models.CharField(max_length=50) 
    shorthand = models.CharField(max_length=12) 

    class Meta: 
     db_table = 'teams_by_event' 
     app_label = 'frcstats'

編輯:: 回溯：

Traceback (most recent call last): 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/core/handlers/base.py", line 149, in get_response 
    response = self.process_exception_by_middleware(e, request) 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/core/handlers/base.py", line 147, in get_response 
    response = wrapped_callback(request, *callback_args, **callback_kwargs) 
    File "/Users/alicen/git/first_robotics/frcstats/views.py", line 1034, in teams_by_event 
    for event in TeamsByEvent.objects.raw(raw_query): 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/db/models/query.py", line 1219, in __iter__ 
    query = iter(self.query) 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/db/models/sql/query.py", line 79, in __iter__ 
    self._execute_query() 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/db/models/sql/query.py", line 113, in _execute_query 
    self.cursor.execute(self.sql, params) 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/db/backends/utils.py", line 79, in execute 
    return super(CursorDebugWrapper, self).execute(sql, params) 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/db/backends/utils.py", line 64, in execute 
    return self.cursor.execute(sql, params) 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/db/backends/sqlite3/base.py", line 322, in execute 
    query = self.convert_query(query) 
    File "/Users/alicen/git/first_robotics/venv/lib/python2.7/site-packages/django/db/backends/sqlite3/base.py", line 330, in convert_query 
    return FORMAT_QMARK_REGEX.sub('?', query).replace('%%', '%') 
TypeError: expected string or buffer

來源

2016-03-02 alicen

我可以看到你的models.py？ – arcegk

@arcegk - 已編輯爲我的models.py添加該表 – alicen

您已在'％s'內有額外的空間，並且在已指出的錯誤位置處有一個右括號。 – serg

看來你把)在錯誤的位置。它不應該像跟隨？

def teams_by_event(request, shorthand): 
    code = TeamsByEvent.objects.filter(shorthand=shorthand) 
    raw_query = '''SELECT event_name, team_number 
        FROM teams_by_event 
        WHERE team_number IN (
        SELECT team_number FROM teams_by_event 
        WHERE shorthand = % s)''' % [code] 

    for event in TeamsByEvent.objects.raw(raw_query): 
     print (event.team_number, event.event_name) 

    return render(request, 'event-info.html', {'info': info})

來源

2016-03-02 05:11:21 jbacker

我也嘗試過，我也遇到同樣的錯誤 - @jbacker – alicen

@alicen，你現在可以試試嗎？我已更新它。 – jbacker

我不得不添加一些括號，並刪除第二個％，但它給了我一個新的錯誤：「預期的字符串或緩衝區」 – alicen

嘗試做兩個獨立的查詢：

subquery = TeamByEvent.objects.filter(event_name__icontains='input').\ 
values_list('team_number' , flat=True) 

query = TeamByEvent.objects.filter(team_number__in=subquery)

來源

2016-03-02 05:29:57 arcegk

看到你的表結構（即模型）和查詢，我敢肯定，你不需要嵌套查詢的。您的疑問：

SELECT event_name, team_number 
FROM teams_by_event 
WHERE team_number IN (SELECT team_number 
        FROM teams_by_event 
        WHERE event_name = '[user inputs event name]' 
        ) ORDER BY team_number;

應返回正是下面的查詢結果：

SELECT event_name, team_number 
FROM teams_by_event 
WHERE event_name = '[user inputs event name]' ORDER BY team_number;

和等效Django的查詢會是這樣的：

TeamsByEvent.objects.filter(event_name='your_event_name')

來源

2016-03-02 06:06:32

我不認爲你完全明白我在做什麼。我想輸入一個事件，取回所有球隊號碼，然後返回每個球隊號碼也與之相關的所有事件。一些團隊號碼將有3個事件相關聯，其他人將只有一個 – alicen

Django Views中的嵌套SQL查詢

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