JSON API來MySQL表

我有一個API請求，我需要它在MySQL數據庫把JSON API來MySQL表

API示例

"items": [ 
    { 
     "market_name": "\u2605 Bayonet", 
     "market_hash_name": "\u2605 Bayonet", 
     "icon_url": "\/\/steamcommunity-a.akamaihd.net\/economy\/image\/-9a81dlWLwJ2UUGcVs_nsVtzdOEdtWwKGZZLQHTxDZ7I56KU0Zwwo4NUX4oFJZEHLbXU5A1PIYQh5hlcX0nvUOGsx8DdQBJjIAVHubSaKQZ53P3NZXMXvYmykdLSxqWkZ7-HkjMIvpIj3u2Y84733gzh_RU_MG_zIYLEdQ45fxiOrdJh0ExF", 
     "name_color": "8650AC", 
     "quality_color": "EB4B4B" 
    }, 
    { 
     "market_name": "\u2605 Bayonet | Blue Steel (Battle-Scarred)", 
     "market_hash_name": "\u2605 Bayonet | Blue Steel (Battle-Scarred)", 
     "icon_url": "\/\/steamcommunity-a.akamaihd.net\/economy\/image\/-9a81dlWLwJ2UUGcVs_nsVtzdOEdtWwKGZZLQHTxDZ7I56KU0Zwwo4NUX4oFJZEHLbXH5ApeO4YmlhxYQknCRvCo04DEVlxkKgpotLu8JAllx8zJYAJA4MmzkL-DkvbiKvXTkzNVucNzj7mX9tWk21Xkr0JvN231JYGcdA47NF3Y81Hoxebs1sftot2XnmcyW1u0", 
     "name_color": "8650AC", 
     "quality_color": "EB4B4B" 
    },

和我的PHP文件

$json = file_get_contents('API Link'); 
$obj = json_decode($json,true); 

$hostname="localhost"; 
$database="API"; 
$username="XxX"; 
$password="XxX"; 

$link = mysql_connect($hostname, $username, $password); 
mysql_select_db($database) or die('Could not select database');

我知道燙使用一個項目，如

$obj['items'][0]['market_name'];

我需要自動將數字從0更改爲7226，並將其添加到數據庫之後。你能幫我嗎？

來源

2016-07-01 Skaci

哪個號碼0到7226的'0'是數組 –

的指數你想創建一個循環，並添加條目7226到您的數據庫？ – Fredster

7226似乎是任意的，背後的任何推理？ – apokryfos

試試這個：

$items = $obj['items']; 
for($i=0; $i<count($items);$i++){ 
    //Do the stuff whatever you want to do inside the loop 
    // $i will change the index from 0 to the last index of array $items 

    $market_name = $items[$i]['market_name']; 
}

來源

2016-07-01 07:50:17 AkshayP

JSON API來MySQL表

回答

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