如何使HEAD請求到pycurl

Question

我需要使用pycurl發送HTTP HEAD請求。

此代碼

curl = pycurl.Curl() 
... 
curl.setopt(curl.CUSTOMREQUEST, "HEAD") 
curl.perform() 

產生一個錯誤：

< HTTP/1.1 200 OK 
* Server nginx/1.6.2 is not blacklisted 
< Server: nginx/1.6.2 
< Date: # No matters 
< Content-Type: text/html; charset=utf-8 
< Connection: keep-alive 
< Cache-Control: no-cache,no-store,must-revalidate 
< Pragma: no-cache 
< Expires: # No matters 
< Last-Modified: # No matters 
< Content-Security-Policy: # No matters 
< X-Frame-Options: SAMEORIGIN 
< X-XSS-Protection: # No matters 
< X-Content-Type-Options: nosniff 
< Content-Encoding: gzip 
* no chunk, no close, no size. Assume close to signal end 
< 
* Operation timed out after 15001 milliseconds with 0 bytes received 
* Closing connection 1 

任何人可以幫助我嗎？

Answer 1

您需要NOBODY選項。如在任何身體請。只是改變CUSTOMREQUEST並不會讓libcurl改變它的行爲方式，它會認爲它會執行一個GET，但是你將它改爲HEAD，然後事情就會變糟。

Answer 2

只是爲了澄清。你不需要做一個CUSTOMREQUEST！僅僅指定一個'NOBODY'選項就足以讓pycurl自己生成一個'HEAD'請求。用PycURL/7.43.0測試libcurl/7.51.0