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我有一個使用2個PHP文件和一個MySql數據庫的示例頁面，並且我試圖在其上使用jQuery無限滾動。我如何從數據庫加載下一組數據？例如，我在我的照片數據庫中有100條記錄，我想要顯示20條記錄，然後在一些滾動條件後顯示20條記錄。如何爲無限滾動分頁查詢結果？
這是我目前的核心：
的index.php
<?php
ob_start();
require_once('images.html');
ob_end_flush();
?>
images.html
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8" />
<title> trata tata</title>
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">
<!--[if lt IE 9]><script src="http://html5shim.googlecode.com/svn/trunk/html5.js"></script><![endif]-->
<link rel="stylesheet" href="./css/style.css" />
<!-- scripts at bottom of page -->
</head>
<body class="demos ">
<nav id="site-nav">
<h1><a href="./index.html">ole tu jest HOME</a></h1>
<h2>Menu 1</h2>
<ul class="docs-list">
<li><a href="../docs/intro.html">11111111</a>
</ul>
<h2>Menu 2</h2>
<ul class="demos-list">
<li><a href="../demos/basic-single-column.html">222222222</a>
<li class="current"><a href="#content">3333333333</a></li>
</ul>
</nav> <!-- #site-nav -->
<section id="content">
<h1>cos tam ....</h1>
<div id="container" class="clearfix">
<?php
// Make a MySQL Connection
mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("test") or die(mysql_error());
// Retrieve all the data from the "test " table
$result = mysql_query("SELECT * FROM foto")
or die(mysql_error());
// store the records of the "TABLENAME" table into $row array and loop through
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
// Print out the contents of the entry
//echo "details: ".$row['id'];
echo '<div class="box photo col3">';
echo "<img src=\"".$row['src']."\" alt=\"wwwwww\" />";
echo '</div>';
}
?>
</div> <!-- #container -->
<script src="./js/jquery-1.7.1.min.js"></script>
<script src="./jquery.masonry.min.js"></script>
<script>
$(function(){
var $container = $('#container');
$container.imagesLoaded(function(){
$container.masonry({
itemSelector : '.box'
});
});
});
</script>
<footer id="site-footer">
szaki <a href="http://desandro.com">sdfsdfdsfsdf</a>
</footer>
</section> <!-- #content -->
</body>
</html>