將ARMv6體系結構添加到使用Xcode 4.5構建的iOS可執行文件的腳本錯誤

Question

您能幫我一下嗎？

如果我使用下面的腳本：

# Find the common base directory for both build 
XCODE_BUILD=${BUILD_ROOT%%/Build*} 
# Change this to the full path where Xcode 4.4 (or below) puts your armv6 output, using the previously derived base 
export ARMV6_EXECUTABLE_PATH="$XCODE_BUILD/Build/Products/Release_armv6-iphoneos/$EXECUTABLE_PATH" 

然後構建失敗，消息如下：

Missing }. 
Command /bin/sh failed with exit code 1 

我做錯了嗎？

感謝您的幫助。

Answer 1

我解決了我的錯誤。

所以如果你從下一行改變上面的行，你的應用程序可以建立，也可以存檔。

# Find the common base directory for both build 
setenv XCODE_BUILD `echo $BUILD_ROOT| sed 's|Build.*||'` 
echo $XCODE_BUILD 
# Change this to the full path where Xcode 4.4 (or below) puts your armv6 output, using the previously derived base 
setenv ARMV6_EXECUTABLE_PATH "$XCODE_BUILD/Build/Products/Release_armv6-iphoneos/$EXECUTABLE_PATH"