我正在開發一個多選題的頁面。用戶只能爲每個問題選擇一個答案。我似乎無法檢索單選按鈕的值(1表示正確答案)。獲取廣播組的價值
這裏是兩個表的結構,我使用包含無線電組
CREATE TABLE IF NOT EXISTS `question` (
`q_id` int(10) NOT NULL AUTO_INCREMENT,
`q_qstn_no` int(11) NOT NULL,
`q_text` varchar(300) NOT NULL,
`q_chpt` int(11) NOT NULL,
PRIMARY KEY (`q_id`)
)
CREATE TABLE IF NOT EXISTS `answer` (
`a_id` int(6) NOT NULL AUTO_INCREMENT,
`q_id` int(10) NOT NULL,
`a_text` varchar(255) NOT NULL,
`a_value` tinyint(1) NOT NULL,
PRIMARY KEY (`a_id`)
)
HTML表單。
<?php
ini_set('display_errors',1);
error_reporting(E_ALL^E_NOTICE);
session_start();
if(isset($_SESSION['tf1_sid']))
{
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<form id="form1" name="form1" method="post" action="ques_page_calc1.php">
<p>Questions</p>
<table width="900" border="0" cellpadding="4">
<?php
// db connect
include("dbconn.php");
// db query for questions
$sql_q = "SELECT q_id, q_qstn_no, q_text FROM question";
$query_q = mysql_query($sql_q) or die("MySQL Error: " . mysql_error());
// start loop for questions
$rad2 = 0;
while($data_q = mysql_fetch_array($query_q, MYSQL_ASSOC)){
// echo "<pre>";
// print_r($data_q);
// echo "</pre>";
//
echo "<tr><td width='25' align='center' valign='top'><label><input name='q_no' size='1' type='hidden' value=". $data_q['q_qstn_no'] .">". $data_q['q_qstn_no'] ."</label></td>";
echo "<td>". $data_q['q_text'] ."<br />";
// db query for answers
$sql_a = "SELECT a_id, a_text, a_value FROM answer WHERE q_id=".$data_q['q_id'];
$query_a = mysql_query($sql_a) or die("MySQL Error: " . mysql_error());
//$rad = 0;
// start loop for answers
while($data_a = mysql_fetch_array($query_a, MYSQL_ASSOC)){
echo "<br /><table width='750' border='0'>";
echo "<tr><td><label><input name='answer_".$rad2."' type='radio' value=". $data_a['a_value'] .">". $data_a['a_text'] . "</label></td></tr>";
echo "</table>";
//$rad++;
}
echo "</tr>";
$rad2++;
}
echo "<tr><td><input name='Submit' type='submit' onClick='ques_page_calc1.php' value='Submit'></td></tr>";
mysql_free_result($query_q);
mysql_free_result($query_a);
include("dbconn.php");
?>
</table>
</form>
</body>
</html>
<?php
}
else
{
header("Location:s_login.php");
}
?>
的PHP文件來獲取值選擇
<?php
ini_set('display_errors',1);
error_reporting(E_ALL^E_NOTICE);
// include db connection file
include("dbconn.php");
session_start();
if(isset($_POST['Submit']))
{
$id = $_SESSION['tf1_sid'];
echo $id;
$correct = 0;
$ev_id = 1;
//db query to obtain i_id
$sql_i = "SELECT i_id FROM ins_stud WHERE s_id = '$id'";
$query_i = mysql_query($sql_i) or die("MySQL Error: " . mysql_error());
$data_i = mysql_fetch_array($query_i, MYSQL_ASSOC);
print_r($data_i);
// capture values from HTML form
if(!empty($_POST['answer_'.$rad2]))
{
foreach(($_POST['answer_'.$rad2]) as $ans)
{
echo $ans;
var_dump($_POST);
if($ans == 1)
$correct = $correct + 1;
}
//echo $correct;
// insert answer to table
//$sql_eval = "INSERT INTO eval_set (ev_id, q_id, response, created) VALUES ('" . $ev_id . "', '" . $ques_no . "', '" . $ans . "', CURDATE())";
//mysql_query($sql_eval) or die ("Error: " . mysql_error());
//}
}
//
// insert result to table
//$sql_result = "INSERT INTO result (r_score, ev_id, s_id, i_id) VALUES ('" . $correct . "', '" . $ev_id . "', '" . $id . "', '" . $data_i . "')";
//mysql_query($sql_result) or die ("Error: " . mysql_error());
//echo "Result: " . $correct . " questions correct.";
//header("Location:ass_result.php");
}
// close db connection
mysql_close($dbconn);
?>
我認爲這是這是造成問題的原因,因爲我不知道如何連接變量name字段$_POST['answer_'.$rad2]
。但是現在這個改變了,PHP文件中的print_r($data_i);
行仍然沒有輸出。
如果我省略了變量,就不可能爲每個問題保留選定的單選按鈕。例如,回答Q1是好的,但當我回答Q2時,回答Q1重置等等。當頁面上有4個問題時,只有一個選定的單選按鈕。每個問題的單選按鈕都是四個一組的。 – 2013-03-21 03:20:29
對不起,我一定錯過了你實際上給單選按鈕同一個問題的同名。只是你有幾個問題,因此每個組別都有不同的名稱。 – mavili 2013-03-21 03:25:16