它說數組是未定義的？

Question

在我的代碼中，我通過for循環中的另一種方法填充數組。我已經證實數組實際上已經被填充了正確的信息，但是當我嘗試返回並使用它時，它說它沒有定義，但是爲什麼？

代碼：

function Data(name, csv){ 
    this.dataTable = null; 
    this.createDataTable(name, csv); 
} 

Data.prototype.createDataTable = function(name, csv){ 
    dataTable = persistence.define(name, { 
     Tank1: "INT", 
     Tank2: "INT", 
     Tank3: "INT", 
     Tank4: "INT", 
     Helicopter: "INT", 
    }); 
    this.fetchData(csv); 
}; 

Data.prototype.fetchData = function(csv){ 
    jQuery.get(csv, function(data) { 
     var result = $.csv.toArrays(data); 
     result.shift(); 
     result.forEach(function (r) { 
      var joinedResult = r.join(); 
      fillDB(joinedResult); 
     }); 
    }); 

    var test = getData(); <--- This is where I am testing the code. 
    var joinedResult = testlolol.join(); 
    var splitData = joinedResult.split(";"); 
    alert(splitData); 
}; 

//This function will fill the database using the parsed array line from the csv file. 
function fillDB(DataArray){ 
    //Wipe local database clean 
    persistence.reset(function(){ 
     //Write schema 
     persistence.schemaSync(function(){ 
      //Add values from the array to their matching columns. 
      var data = new dataTable(); 
      var splitData = DataArray.split(";"); 
      data.Tank1 = splitData[0]; 
      data.Tank2 = splitData[1]; 
      data.Tank3 = splitData[2]; 
      data.Tank4 = splitData[3]; 
      data.Helicopter = splitData[4]; 
      persistence.add(data); 
      persistence.flush(); 
     }); 
    }); 
} 

function deleteData(column, operator, value){ 
     persistence.flush(function(){ 
     dataTable.all().filter(column,operator , value).destroyAll(); 
     }); 
} 

function addData(Tank1, Tank2, Tank3, Tank4, Helicopter){ 
     var data = new dataTable(); 
     data.Tank1 = Tank1; 
     data.Tank2 = Tank2; 
     data.Tank3 = Tank3; 
     data.Tank4 = Tank4; 
     data.Helicopter = Helicopter; 
     persistence.add(data); 
     persistence.flush(); 
} 

function getData(){ 
    var newDataArray = new Array(); 
    dataTable.all().list(function(tasks){ 
     tasks.forEach(function (r) { 
      var tTank1 = r.Tank1; 
      var tTank2 = r.Tank2; 
      var tTank3 = r.Tank3; 
      var tTank4 = r.Tank4; 
      var tHelicopter = r.Helicopter; 
      newDataArray.push(tTank1, tTank2, tTank3, tTank4, tHelicopter); 
      tempTest(newDataArray); 
     }); 
    }); 
} 

function tempTest(array){ 
    var newDataArray = new Array(); 
    newDataArray.push(array); 
    alert(newDataArray); <-- these contain the correct values 
    return newDataArray; 
} 

所以我希望有人知道這個問題的答案？也談我的代碼和/或交格式的其他批評亦歡迎:)

Answer 1

不必返回任何值

function getData(){ 
    var newDataArray = new Array(); 
    dataTable.all().list(function(tasks){ 
     tasks.forEach(function (r) { 
      var tTank1 = r.Tank1; 
      var tTank2 = r.Tank2; 
      var tTank3 = r.Tank3; 
      var tTank4 = r.Tank4; 
      var tHelicopter = r.Helicopter; 
      newDataArray.push(tTank1, tTank2, tTank3, tTank4, tHelicopter); 
      tempTest(newDataArray); 
     }); 
    }); 
    return newDataArray 
}