從csv文件讀取數據 - 找不到有效源的文件例外

Question

從網上讀取csv文件時出現問題。我得到一個文件未找到異常。這是來源：http://data.okfn.org/data/core/s-and-p-500-companies/r/constituents.csv 如果我可以輕鬆打開它，那麼該文件怎麼可能找不到？我在這裏錯過了什麼？

package Investing; 


import java.io.BufferedReader; 
import java.io.FileReader; 
import java.io.IOException; 

public class Main { 

    public static void main(String[] args) { 

    String csvFile = "http://data.okfn.org/data/core/s-and-p-500-  companies/r/constituents.csv"; 
    String line = ""; 
    String cvsSplitBy = ","; 


    try (BufferedReader br = new BufferedReader(new FileReader(csvFile))) { 

     while ((line = br.readLine()) != null) { 

      // use comma as separator 
      String[] data = line.split(cvsSplitBy); 

      System.out.println(data); 

     } 

    } catch (IOException e) { 
     e.printStackTrace(); 
    } 


} 
} 

Answer 1

FileReader用於本地文件。 請參閱：Read remote .csv file using opencsv用於讀取遠程CVS文件。

另一種替代以讀取遠程文件：

public static void main(String[] args) { 

    String csvFile = "http://data.okfn.org/data/core/s-and-p-500-companies/r/constituents.csv"; 

    try { 
     URL url12 = new URL(csvFile); 
     URLConnection urlConn = url12.openConnection(); 
     InputStreamReader inStream = new InputStreamReader(urlConn.getInputStream()); 
     BufferedReader buff = new BufferedReader(inStream); 

     String line = buff.readLine(); 
     line = buff.readLine(); 
     while (line != null) { 

      System.out.println(line); 
      line = buff.readLine(); 
     } 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 

}