PHP PDO列表（非法串）

Question

<?php 
    $user = $db->query("SELECT * FROM users")->fetchAll(PDO::FETCH_ASSOC); 

     foreach($user as $row) { 
     echo "<tr>"; 

      echo '<td>".$row['username']."</td>'; 
      echo'<td>'.$row["email"].'</td>'; 
      echo'<td>'.$row["password"].'</td>'; 
      echo '<td>'; 
       echo '<a href="">Edit</a>'; 
       echo '<a href="">Delete</a>'; 
      echo ' </td>'; 
     echo '</tr>'; 
     } 

?> 

Answer 1

你有一個問題與類型，您使用的報價。這應該起作用。

<?php 
     $user = $db->query("SELECT * FROM users")->fetchAll(PDO::FETCH_ASSOC); 

      foreach($user as $row) { 
      echo "<tr>"; 

       echo '<td>'.$row['username'].'</td>'; 
       echo '<td>'.$row["email"].'</td>'; 
       echo '<td>'.$row["password"].'</td>'; 
       echo '<td>'; 
        echo '<a href="">Edit</a>'; 
        echo '<a href="">Delete</a>'; 
       echo ' </td>'; 
      echo '</tr>'; 
      } 

    ?> 

Answer 2

最簡單的方法是

<?php 
    $user = $db->prepare("SELECT * FROM users")->execute()->fetchAll(PDO::FETCH_ASSOC); 

    foreach($user as $row) { ?> 
<tr> 
    <td><?php echo $row['username']; ?></td> 
    <td><?php echo $row['email']; ?></td> 
    <td><?php echo $row['password']; ?></td> 
    <td> 
     <a href="">Edit</a> 
     <a href="">Delete</a> 
    </td> 
</tr> 
<?php 
    } 
?>