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我想是做的就是這個查詢的學說:怎麼做createQuiry聯接教義或DQL
SELECT *
FROM `reservation`
JOIN res_chauf ON reservation.reservation_id = res_chauf.reservation_id
WHERE res_chauf.chauffeur_id =1
教義/ Symfony2中與DQL 我知道如何做到這一個選擇這樣:
$qb = $em->createQueryBuilder();
$qb->select('c')
->from('myBundle:Client', 'c')
->where('c.name LIKE :data')
->orderBy('c.name', 'ASC')
->setParameter('data', '%'.$data.'%');
$query = $qb->getQuery();
$entities = $query->getResult();
,但現在我已經加入兩個表
一些幫助,請
謝謝