Python的步行目錄結構和拉鍊子目錄

Question

我跑到下面的代碼：

import zipfile 
import glob 
import datetime 
import os 
from collections import defaultdict 
from shutil import copyfile 

src = 'X:\\' 

for name in glob.glob('X:\*'): 
    print name 

dict_date = defaultdict(lambda : defaultdict(list)) 
for fil in os.listdir(src): 
     if os.path.isfile(os.path.join(src, fil)): 
     date, logs = fil.split('_')[0], fil.split('_')[2] 
     dict_date[date][logs].append(fil) 

for date in dict_date: 
    for logs in dict_date[date]: 
     try: 
      os.makedirs(os.path.join(src, date, logs)) 
      except os.error: 
      pass 
     for fil in dict_date[date][logs]: 
      copyfile(os.path.join(src, fil), os.path.join(src, date, logs, fil)) 



for date in dict_date: 
    with ZipFile(os.path.join(path, '{0}.zip'.format(date)), 'w') as myzip: 
     for logs in dict_date[date]: 
      for fil in os.listdir(os.path.join(path, date, logs)): 
       if fil.endswith('.log'): 
        myzip.write(os.path.join(path, date, logs, fil)) 

下面是結果：

>>> 
X:\082012 
X:\092012 
X:\20120830 
X:\20120830_7Days_ISDA_Logs_HS.zip 
X:\20121001 
X:\20121002 
X:\20121003 
X:\20121004 
X:\20121005 
X:\20121006 
X:\20121007 
X:\20121008 
X:\20121009 
X:\20121010 
X:\20121011 

Traceback (most recent call last): 
    File "C:\Documents and Settings\tyoffe\Desktop\isda_zip.py", line 31, in <module> 
    with ZipFile(os.path.join(path, '{0}.zip'.format(date)), 'w') as myzip: 
NameError: name 'ZipFile' is not defined 
>>> 

Answer 1

你應該使用：

with zipfile.ZipFile(os.path.join(path, '{0}.zip'.format(date)), 'w') as myzip: 

還是應該做：

from zipfile import ZipFile