如何將下拉值存入.php文件

Question

我需要將選定的下拉值存入我的.php文件，該文件實際上是發送郵件文件。

當我從下拉列表中選擇6個選項中的一個時，我想要選擇的選項作爲電子郵件的「主題」包含在郵件中。

這裏是我的HTML代碼

<span class="custom-dropdown big"> 
    <select id="mounth" name="mounth"> 
     <option value="default">-- Domain name --</option> 
     <option value="value1" rel="icon-temperature">value1</option> 
     <option value="value2">value2</option> 
     <option value="value3">value3</option> 
     <option value="value4">value4</option> 
     <option value="value5">value5</option> 
     <option value="value6">value6</option> 
    </select> 
    <input type="hidden" id="changeme" name="changeme" /> 
</span> 

通過電子郵件形式

<div class="modal fade" id="popup-moda"> 
    <div class="modal-dialog"> 
     <div class="modal-content"> 
      <div class="modal-header"> 
       <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span id="spanhide" aria-hidden="true">&times;</span></button> 
       <h4 class="modal-title">Contact Us</h4> 
      </div> 
      <form action="" method="post" name="form" id="forms"> 
       <div class="modal-body"> 
        <div id="domain" name="domain"></div> 
        <input required id="name" name="name" placeholder="Name" type="text"> 
        <input required id="email" name="email" placeholder="Email" type="text"> 
        <textarea id="msg" name="msg" placeholder="Message"></textarea> 
       </div> 
       <div class="modal-footer"> 
        <button type="button" class="btn btn-default" data-dismiss="modal">Close</button> 
        <button type="submit" class="btn btn-primary">Send</button> 
        <div id="success" style="color: blue;"></div> 
       </div> 
      </form> 
     </div><!-- /.modal-content --> 
    </div><!-- /.modal-dialog --> 
</div><!-- /.modal --> 

這裏是我的JS代碼，實際上顯示選定的選項，但只作爲文本發送電子郵件之前 。

$(document).ready(function(){ 

$('.popup').click(function(e){ 
    e.preventDefault(); 
    $('#domain').html('<b>' + $('#mounth').val() + '</b>'); 
    $('#popup-moda').modal('show'); 
     return false; 
}); 
}); 

我的PHP文件

<?php 
$name = $_POST['name']; 
$email = $_POST['email']; 
$msg = $_POST['msg']; 

$to = 'example@example.com'; 
$subject = 'New Customer Enquiry'; 
$msg = <<<EMAIL 
Subject: $subject 
Message: $msg 
From: $name 
Email: $email 
EMAIL; 
$headers = 'From:' . $email; 

if (filter_var($email, FILTER_VALIDATE_EMAIL)) { 
mail($to, $subject, $msg, $headers); mail. 

echo "Thank you for your email! We will reply as soon as possible."; 
} 
else 
{ 
echo "Invalid Email, please provide a correct email address."; 
} 

?> 

謝謝你們。任何輸入是讚賞！

Answer 1

將select放入您的form之內，以便將所選值與其餘的表單參數一起發送到服務器。

<form action="" method="post" name="form" id="forms"> 
    <!-- ... --> 
    <select id="mounth" name="mounth"> 
     <!-- options --> 
    </select> 
    <!-- ... --> 
</form> 

然後在你的PHP文件：

$subject = $_POST['mounth']; 

然後在主題中使用它。

編輯：

然後你就可以隱藏的輸入添加到您的形式與名稱，在選擇下拉列表的值添加到它：

<form action="" method="post" name="form" id="forms"> 
    <!-- form stuff --> 
    <input type="hidden" id="hiddenMounth" name="mounth" value="" /> 
</form> 

再聽聽select的onchange ：

$('#mounth').on('change', function() { 
    $('#hiddenMounth').val($(this).val()); 
}); 

然後在你的PHP：

$subject = $_POST['mounth'];