如何實現Hibernate 3.0的

Question

嗨MySQL的DATE_SUB（）函數，我必須寫在Hibernate查詢像

SELECT * FROM `tablename` where created_at> DATE_SUB(curdate(),INTERVAL 7 DAY) 

處於休眠

。我已發佈有關此主題的查詢。但沒有人幫助我。在hiberanate中可以寫這樣的查詢嗎？請回復。

Answer 1

您可以使用一個native SQL query

String sql = "SELECT * FROM tablename WHERE created_at > DATE_SUB(curdate(), INTERVAL 7 DAY)" 
Query query = session.createSQLQuery(sql); 
List result = query.list(); 

或者你也可以使用Hibernate的標準Restrictions.sqlRestriction

String sqlWhere = "{alias}.created_at > DATE_SUB(curdate(), INTERVAL 7 DAY)"; 
Criteria criteria = session.createCriteria(MyEntity.class); 
criteria.add(Restrictions.sqlRestriction(sqlWhere)); 
List result = criteria.list(); 

希望有所幫助。

Answer 2

String sql1 = "select uh.ServiceDate from tablename uh WHERE uh.ServiceDate >= DATE_SUB(curdate(), INTERVAL 1 YEAR)"; 

Query query1 = session.createSQLQuery(sql1); 

List result = query1.list(); 

     use this list in HQL 

String queryString = "delete from tablename u where u.serviceDate in (:result)"; 
query =session.createQuery(queryString); 
query.setParameterList("result", result); 

Answer 3

您還可以擴展hibernate的mysql方言以支持date_add函數。

public class CommonMySQL5InnoDBDialect extends MySQL5InnoDBDialect { 
    public CommonMySQL5InnoDBDialect() { 
     super(); 
     //mysql date_add function support. 
     registerFunction("date_add_interval", new SQLFunctionTemplate(DateType.INSTANCE, "date_add(?1, INTERVAL ?2 ?3)")); 
    } 
} 

然後你就可以使用HQL中的註冊函數。

from tablename where created_at > date_add_interval(curdate(), 7 DAY)