preg替換爲所需值

Question

我使用商店的座標並手動將座標作爲lang和long添加到數據庫。有時候會錯誤地批准座標。

讓我舉個例子來說吧。

例如; 朗33.4534543543錯誤。但有時我把鍵盤和它變得像，

33.4534543543< 

或 33.4534543543， 或 ，（空間）33.4534543543 <

我怎樣才能得到只有33.4534543543？

Answer 1

preg_match_all

要找到包含多個匹配的字符串匹配，你可以使用preg_match_all ：

$strings = "33.4534543543< 
33.4534543543, 
, 33.4534543543<"; 
$pattern = "!(\d+\.\d+)!"; 

preg_match_all($pattern,$strings,$matches); 

print_r($matches[0]); 

輸出

Array 
(
    [0] => 33.4534543543 
    [1] => 33.4534543543 
    [2] => 33.4534543543 
) 

的preg_match

要找到可以使用preg_match一個字符串匹配。

$string = "33.4534543543<"; 
$pattern = "!(\d+\.\d+)!"; 

if(preg_match($pattern,$string,$match)){ 
print($match[0]); 
} 

輸出

33.4534543543 

的preg_replace

要更換什麼，是不是你現有的字符串中想你會使用preg_replace什麼：

$string = preg_replace('![^\d.]!','',$string); 

一個例子：

$strings = "33.4534543543< 
33.4534543543, 
, 33.4534543543<"; 

$strings_exp = explode("\n",$strings); 

$output = ''; 
foreach($strings_exp as $string){ 
$output.= "String '$string' becomes "; 
$new_string = preg_replace('![^0-9.]!','',$string); 
$output.= "'$new_string'\n"; 
} 

echo $output; 

輸出

String '33.4534543543<' becomes '33.4534543543' 
String '33.4534543543,' becomes '33.4534543543' 
String ', 33.4534543543<' becomes '33.4534543543' 

Answer 2

聽起來像你想要做一個preg_match：http://phpfiddle.org/main/code/z6q-a1d

$old_vals = array(
    '33.4534543543<', 
    '33.4534543543,', 
    ', 33.4534543543<' 
); 

$new_vals = array(); 

foreach ($old_vals as $val) { 
    preg_match('(\d*\.?\d+)',$val, $match); 
    array_push($new_vals, $match[0]); 
} 

print_r($new_vals); 

輸出

Array (
    [0] => 33.4534543543, 
    [1] => 33.4534543543, 
    [2] => 33.4534543543 
)