puzzle1= [
[7,0,0,0,0,0,2,1,8],
[0,4,8,6,2,9,0,0,0],
[0,0,3,0,0,1,0,0,0],
[0,0,7,0,0,8,0,3,2],
[0,0,9,7,0,6,5,0,0],
[6,8,0,1,0,0,7,0,0],
[0,0,0,2,0,0,4,0,0],
[0,0,0,4,1,5,8,7,0],
[3,5,4,0,0,0,0,0,6]
]
def eliminate_values(puzzle):
redo = False
for i in range(9):
for j in range(9):
if puzzle[i][j]==0 or isinstance(puzzle[i][j], list):
puzzle[i][j] = []
for num in range(1,10):
num_check = True;
for x in range(9):
if puzzle[i][x]==num:
num_check = False
if puzzle[x][j]==num:
num_check = False
if i<3:
aa=0
elif i<6 and i>2:
aa=3
else:
aa=6
if j<3:
bb=0
elif j<6 and j>2:
bb=3
else:
bb=6
for a in range(3):
for b in range(3):
if puzzle[a+aa][b+bb]==num:
num_check = False
if num_check:
puzzle[i][j].append(num)
if len(puzzle[i][j]) == 1:
puzzle[i][j] = puzzle[i][j][0]
redo = True;
if redo:
eliminate_values(puzzle)
else:
print(puzzle)
return puzzle
puzzle=eliminate_values(puzzle1)
print(puzzle)
控制檯:
[[7, 9, 6, 3, 5, 4, 2, 1, 8], [1, 4, 8, 6, 2, 9, 3, 5, 7], [5, 2, 3, 8, 7, 1, 9, 6, 4], [4, 1, 7, 5, 9, 8, 6, 3, 2], [2, 3, 9, 7, 4, 6, 5, 8, 1], [6, 8, 5, 1, 3, 2, 7, 4, 9], [8, 7, 1, 2, 6, 3, 4, 9, 5], [9, 6, 2, 4, 1, 5, 8, 7, 3], [3, 5, 4, 9, 8, 7, 1, 2, 6]]
None
評論:
我是新來的Python,但我不明白爲什麼印刷是函數內的工作,不在它被返回到主程序之後。 (希望它打印兩次,但只打印一次,然後「無」)
你可能應該在'if redo'中做'return elimin_values(puzzle)'。 –
'if redo: return elimin_values(puzzle)' –