程序趕上算術異常，並且將展示finally塊

-3

我有問題。編碼如下所示。當我運行程序並輸入「aaa」時，它顯示錯誤，因爲它只捕獲算術異常。如何添加適當的代碼來克服基於問題發生的異常？程序趕上算術異常，並且將展示finally塊

import java.io.* ; 
public class FinallyPractice1 
{ 
    public static void main(String []) 
    { 
     BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in)); 
     String inData; int num=0, div=0; 
     try 
     { System.out.println("Enter the numerator:"); 
      inData=stdin.readLine(); 
      num=Integer.parseInt(inData); 

      System.out.println("Enter the divisor:"); 
      inData=stdin.readLine(); 
      div=Integer.parseInt(inData); 

      System.out.println(num+"/"+div+" is "+(num/div)); 
     } 
     catch(ArrayIndexOutOfBoundsException ae) 
     { 
     System.out.println("You can't divide "+ num + " by " + div); 
     } 
     catch(ArithmeticException aex) 
     { 
      System.out.println("You entered not a number: " + inData); 
     } 
     finally 
     { 
     System.out.println("If the division didn't work, you entered bad data."); 
     } 
      System.out.println("Good-by"); 
    } 
}

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我已經找到答案！編碼是象下面這樣：

import java.io.* ; 
    public class FinallyPractice1 
    { 
     public static void main(String [] a) throws IOException 
     { 
      BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in)); 
      String inData; int num=0, div=0; 
      try 
      { System.out.println("Enter the numerator:"); 
       inData=stdin.readLine(); 
       div=Integer.parseInt(inData); 

       System.out.println("Enter the divisor:"); 
       inData=stdin.readLine(); 
       div=Integer.parseInt(inData); 

       System.out.println(num+"/"+div+" is "+(num/div)); 
      } 
      catch(ArithmeticException ae) 
        { 
         System.out.println("ArithmeticException by " + div); 
        } 
        catch(ArrayIndexOutOfBoundsException ae) 
        { 
        System.out.println("You can't divide "+ num + " by " + div); 
       } 
        catch(NumberFormatException ae) 
        { 
        System.out.println("NumberException"); 
       } 
        finally 
        { 
        System.out.println("If the division didn't work, you entered bad data."); 
       } 
         System.out.println("Good-by"); 
     } 
    }

來源

2012-10-12 Rebecca

什麼碼例外......？ –

您忘記了粘貼代碼。點擊[編輯]，並添加它。 – dasblinkenlight

您是否介意加入你的源代碼？謝謝。 – reporter

當你是故意輸入錯誤數據「AAA」，您的發言：

div=Integer.parseInt(inData);

將拋出一個NumberFormatException。您可以爲此添加一個catch塊：

... 
} catch (NumberFormatException nfe) { 
    System.err.println(nfe); 
    // more error handling 
} catch ...

來源

2012-10-12 14:29:37 Reimeus

添加一個更catch塊，像這樣：

} catch(ArrayIndexOutOfBoundsException ae) { 
     System.out.println("You can't divide "+ num + " by " + div); 
    } catch(ArithmeticException aex) { 
     System.out.println("You entered not a number: " + inData); 
    } finally { 
     //.... 
    }

Generaly，您可以根據需要儘可能多的catch塊添加到單個try塊。但要記得給他們正確的順序 - 首先放置更具體的例外，更通用 - 最後。

如果你想捕捉任何可能的例外，您可以使用Throwable類：

try { 
    // some potentially dangerous code 
} catch (Throwable th) { 
    // process error somehow 
}

來源

2012-10-12 14:19:58 HitOdessit

我已經嘗試編譯和運行，但它表明標識預期的錯誤。 – Rebecca

您是否導入了ArithmeticException類？ – HitOdessit

已經導入 – Rebecca

添加幾個catch blocks來處理異常。

catch(ArithmeticException ae) 
     { 
      System.out.println("ArithmeticException by " + div); 
     } 
     catch(ArrayIndexOutOfBoundsException ae) 
     { 
     System.out.println("You can't divide "+ num + " by " + div); 
     } 
     catch(IOException ae) 
     { 
     System.out.println("IOException"); 
     } 
     finally 
     { 
     System.out.println("If the division didn't work, you entered bad data."); 
     } 
      System.out.println("Good-by");

來源

2012-10-12 14:22:55 amicngh

您可以使用新的multi-catch。它具有從

catch (ArithmeticException |ArrayIndexOutOfBoundsException ae)

我會建議你抓你期待，而不僅僅是一條毯子的Throwable或異常

來源

2012-10-12 14:31:38 RNJ

程序趕上算術異常，並且將展示finally塊

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