0
雖然合併查詢是差異數量,同時結合querys和個人查詢
SELECT
stdt.`DIST_VC_DNE`,
COUNT(Farmer_ID) AS Farmer_Cnt,
SUM(
CASE
WHEN STATUS = 'Analysed' THEN 1
ELSE 0
END
) AS Analysed_Cnt
FROM
`tt_mao_soil_sample_dtls` tms
INNER JOIN tt_mao_soil_farmer_dtls FAR ON FAR.`Soil_Sample_ID` = tms.`Soil_Sample_ID`
INNER JOIN `st_com_dist` STDT ON STDT.DIST_VC_DC = tms.District_ID
WHERE
Far.print_status IS NULL
AND Is_active = 'Y'
AND stl_user_id = 2222
AND Unique_ID LIKE '2016-17%'
GROUP BY
District_ID;
和ResultSet是
DIST_VC_DNE | Farmer_Cnt | Analysed_Cnt
----------------------------------------
AP 24340 20177
TS 4 0
在寫indivudual查詢 -
SELECT DIST_VC_DNE,COUNT(*) AS Analysed_Cnt
FROM tt_mao_soil_sample_dtls
WHERE `district_id`=10 AND Is_active='Y' AND stl_user_id=2222
AND Unique_ID LIKE '2016-17%';
和ResultSet是
DIST_VC_DNE | Analysed_Cnt
---------------------------
AP 13065 <===This is the correct result
請幫幫我。 –
在Join查詢中,您還在比較Soil_Sample_ID,那是怎麼回事?.....你能更新SQLFiddle還是示例表格數據和你的需求... –
在第二個查詢中,還有一個條件'district_id = 10'。 – Blank