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我試圖使用Laravel雄辯實現嵌套結果。Lumen/Laravel雄辯有很多通過嵌套結果
我的邏輯: 城市,社區,塊
一個城市有很多社區
阿附近有許多塊
的結果,我想acomplish:
City
Neighbourhoods
Blocks
數據應該是:
[
{
id: 1,
name: "New York",
neighbourhoods: [
{
id: 1,
name: "Neighbourhood 1",
city_id: 1,
blocks: [
{
id: 1,
name: "Neighbourhood 1 Block 1",
neighbourhood_id: 1
},
{
id: 2,
name: "Neighbourhood 1 Block 2",
neighbourhood_id: 1
}
]
},
{
id: 2,
name: "Neighbourhood 2",
city_id: 1,
blocks: [
{
id: 3,
name: "Neighbourhood 2 Block 1",
neighbourhood_id: 2
},
{
id: 4,
name: "Neighbourhood 2 Block 2",
neighbourhood_id: 2
}
]
}
]
}
]
種
型號:
City.php
public function neighbourhood()
{
return $this->hasMany('App\Neighbourhood');
}
public function block()
{
return $this->hasManyThrough('App\Block', 'App\Neighbourhood', 'city_id', 'neighbourhood_id', 'id');
}
Neighbourhood.php
public function city()
{
return $this->belongsTo('App\City');
}
public function block()
{
return $this->hasMany('App\Block');
}
Block.php
public function neighbourhood()
{
return $this->belongsTo('App\Neighbourhood');
}
實際的結果使我這個:
[
{
"id": 1,
"name": "Ney York",
"neighbourhoods": [
{
"id": 1,
"city_id": 1,
"name": "Heighbourhood 1"
},
{
"id": 2,
"city_id": 1,
"name": "Heighbourhood 2"
},
{
"id": 4,
"city_id": 1,
"name": "Păcurari"
}
],
"blocks": [
{
"id": 1,
"name": "Heighbourhood 1 Block 1",
"neighbourhood_id": 1,
"city_id": 1
},
{
"id": 2,
"name": "Heighbourhood 1 Block 2",
"neighbourhood_id": 1,
"city_id": 1
}
]
}
]
我想獲得嵌套結果。有沒有辦法做到這一點?我錯過了什麼?
當然,我可以用PHP foreach循環完成,但這將是手動工作。我想知道是否可以直接從查詢中獲得結果。
謝謝。
SOLUTION:
$result = City::with('neighbourhoods.blocks')->get();
天啊!你不知道你救了我多少!非常非常感謝你! –