笨 - 選擇其中id不（另一個查詢結果）

Question

我工作到酒店預訂系統，我目前正試圖選擇可用房間（不保留）。

Rooms DB Structure: 
ID 
ROOM NAME 
CAPACITY 

HOTEL RESERVATIONS DB STRUCTURE: 
ID 
CHECK_IN 
CHECK_OUT 
ROOMS 
... 

這是我當前的代碼：

function searchFreeRooms($data){ 
    $check_in = $data['fields']['check_in']; 
    $check_out = $data['fields']['check_out']; 
    $this->db->select("*"); 
    $this->db->from('core_hotel_rooms'); 
    $this->db->where("id NOT IN (select rooms,total_guests from res_hotel where check_in <= '$check_in' AND check_out >= '$check_in' OR check_in <= '$check_out' AND check_out >= '$check_out' OR check_in >= '$check_in' AND check_out <= '$check_out') "); 
    $query = $this->db->get(); 
    return $query->result(); 
} 

用戶可以預訂多間客房在一個時間，並預留房間ID是存儲在用逗號前分隔欄「房間」：2，3， 5

以我前，室中存在的該列不應該被顯示，但遇到麻煩，因爲被選擇逗號之前僅第一ID（室），例如：2,3,5->僅2被選擇和3,5仍然顯示在我的前面。

問題是在這裏：$this->db->where("id NOT IN (select rooms,total_guests from res_hotel where check_in <= '$check_in' AND check_out >= '$check_in' OR check_in <= '$check_out' AND check_out >= '$check_out' OR check_in >= '$check_in' AND check_out <= '$check_out') ");

我嘗試這樣做：$this->db->where("id NOT IN (1, 2) ");和它的作品完美，但不上法第二查詢。

對不起，我的英語...

非常感謝所有那些誰可以幫助！

Answer 1

最後，我已經解決了我的問題！

工作代碼：

function searchFreeRooms($data){ 
    $check_in = $data['fields']['check_in']; 
    $check_out = $data['fields']['check_out']; 
    $query1 = $this->db->query("select rooms from res_hotel where (check_in <= '$check_in' AND check_out >= '$check_in') OR (check_in <= '$check_out' AND check_out >= '$check_out') OR (check_in >= '$check_in' AND check_out <= '$check_out')"); 
    $query1_result = $query1->result(); 
    $room_id= array(); 
    foreach($query1_result as $row){ 
    $room_id[] = $row->rooms; 
    } 
    $room = implode(",",$room_id); 
    $ids = explode(",", $room); 
    $this->db->select("*"); 
    $this->db->from('core_hotel_rooms'); 
    $this->db->where_not_in('id', $ids); 
    $query = $this->db->get(); 
    return $query->result(); 
} 

非常感謝！

Answer 2

這是您的問題的解決方案。希望這有助於：

function searchFreeRooms($data){ 
    $check_in = $data['fields']['check_in']; 
    $check_out = $data['fields']['check_out']; 

    $query1 = $this->db->query("select rooms from res_hotel where check_in <= '".$check_in."' AND check_out >= '".$check_in."' OR check_in <= '".$check_out."' AND check_out >= '".$check_out."' OR check_in >= '".$check_in."' AND check_out <= '".$check_out."'")->result_array(); 
    $room_id= array(); 
    foreach($query1 as $row){ 
    $room_id[] = $row->rooms; 
    } 
    $room = implode(",",$room_id); 

    $query = $this->db->query("select * from rooms where id not in (".$room.")"); 

     return $query->result(); 
    } 

Answer 3

考慮使用括號

$this->db->where("id NOT IN (select rooms,total_guests from res_hotel where (check_in <= '$check_in' AND check_out >= '$check_in') OR (check_in <= '$check_out' AND check_out >= '$check_out') OR (check_in >= '$check_in' AND check_out <= '$check_out')) "); 

Answer 4

$result = $this->db->select('room') 
    ->get('your_table'); 

    foreach($result as $item) { 
     $array[] = $item['id'];   
    } 
    $a = implode(',', $array); 

$this->where_not_in('id', $a); 

做這樣的事情。