java.sql.SQLException：參數值無效：java.io.NotSerializableException

Question

這是我的SQL連接類的代碼，我收到錯誤消息。

public class SqlConnection { 
    static Connection con; 
....... 

    static public ResultSet getData(String sql, List<LogModel> alist) 
      throws ClassNotFoundException, SQLException { 
     PreparedStatement pst = con.prepareStatement(sql); 
     if (alist != null) { 
      for (int i = 1; i <= alist.size(); i++) { 
       pst.setObject(i, alist.get(i-1)); //Exception at this Line 
      } 
     } 
     ResultSet rs = pst.executeQuery(); 
     return rs; 
    } 
} 

這裏是LogAction類我在哪裏調用這個函數getdata()。

public class LogAction extends ActionSupport implements ModelDriven<LogModel>, Preparable { 

    LogModel log = null; 
    List<LogModel> alist = null; 
    public static final String FAILURE = "failure"; 

    @Override 
    public void prepare() throws Exception { 
     log = new LogModel(); 
     alist = new ArrayList<LogModel>(); 
    } 

    @Override 
    public LogModel getModel() { 
     return log; 
    } 

    public String login() throws ClassNotFoundException, SQLException { 
     String sql = "Select username,password from registration where username=? and password=?"; 
     alist.add(log); 
     System.out.println(alist); 
     ResultSet rs = SqlConnection.getData(sql, alist); 
     if (rs.next()) { 
      return SUCCESS; 
     } else 
      return FAILURE; 
    } 
} 

Answer 1

修改代碼以

static public ResultSet getData(String sql, String username, String password) 
     throws ClassNotFoundException, SQLException { 
    PreparedStatement pst = con.prepareStatement(sql); 
    pst.setString(1, username); 
    pst.setString(2, password); 
    ResultSet rs = pst.executeQuery(); 
    return rs; 
} 

設置模型對象準備好的語句的參數使得非感。

Answer 2

我確定PreparedStatement不知道如何在LogModel上設置對象。我的建議是將其分解爲SQL原語，以便知道如何處理它。

您的代碼需要很多工作。您沒有正確關閉JDBC資源。你的LogAction類沒有意義。這一小部分代碼很有問題。我會擔心你的應用程序。