PDO插入錯誤 - 執行（array（））;

我試圖做一個登記制度，和我得到這個錯誤：PDO插入錯誤 - 執行（array（））;

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''=L&myPRwgOSB?V_execute(Array) #1 {main} thrown in /home/**/public_html/forum/register-cmd.php on line 58

，我不知道爲什麼。代碼如下：它有什麼問題？

<?php 
include('./includes/connect.php'); 
/* START VARIABLES */ 
$submit = $_POST['submit']; 

$username = clean($_POST['username']); 

$email = clean($_POST['email']); 
$repeatedemail = clean($_POST['remail']); 

$password = clean($_POST['password']); 
$repeatedpassword = clean($_POST['rpassword']); 

$year = (int) $_POST['year']; 
$day = (int) $_POST['day']; 
$months = array("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"); 

if(in_array(ucwords($_POST['month']), $months)) { 
    $dob = $_POST['month'] . " " . $day . ", " . $year; 
} else { 
    header('Location: register.php?error=nonexist'); 
} 

$referrer = $_POST['referrer']; 

$recieve_emails = (int) $_POST['getemail']; 
$view_signatures = (int) $_POST['sig']; 
/* END VARIABLES */ 
if(isset($username) && isset($submit) && isset($email) && isset($repeatedemail) && isset($password) && isset($repeatedpassword) && isset($year) && isset($day) && isset($_POST['month']) && isset($recieve_emails) && isset($view_signatures)) { 
    if($email == $repeatedemail) { 
     if($password == $repeatedpassword) { 
      $check_user = $con->prepare("SELECT * FROM users WHERE username = :username"); 
      $check_user->execute(array(
       ":username" => $username 
      )); 
      if($check_user->rowCount() == 1) { 
       header('Location: register.php?error=usernametaken'); 
      } else { 
       $check_email = $con->prepare("SELECT * FROM users WHERE email = :email"); 
       $check_email->execute(array(
        ":email" => $email 
       )); 
       if($check_email->rowCount() == 1) { 
        header('Location: register.php?error=emailtaken'); 
       } else { 
        $salt = salt(); 

        $hashedPassword = sha1($pepper . $password . $salt); 
        $insert = $con->prepare("INSERT INTO users ('username', 'password', 'salt', 'email', 'dob', 'recieve_emails', 'view_signatures') VALUES (:username, :password, :salt, :email, :dob, :recieve_emails, :view_signatures)"); 
        $insert->execute(array(
         ":username" => $username, 
         ":password" => $hashedPassword, 
         ":salt" => $salt, 
         ":email" => $email, 
         ":dob" => $dob, 
         ":recieve_emails" => $recieve_emails, 
         ":view_signatures" => $view_signatures 
        )); 
        header('Location: index.php?success=registered'); 
        exit(); 
       } 
      } 
     } else { 
      header('Location: register.php?error=nomatchpassword'); 
     } 
    } else { 
     header('Location: register.php?error=nomatchemail'); 
    } 
} else { 
    header('Location: index.php'); 
} 
?>

來源

2014-02-16 user3186081

哪些查詢是第58行？ –

我不知道有多少完全相同的問題已被問到。 –

儘管如此，仍然以相同的熱情回答。對於這對夫妻來說，總有一個新來的新人渴望着。 –

MySQL的列封裝是通過反引號（`）而不是單引號（'）完成的。所以，你需要改變查詢語法

INSERT INTO users ('username', 'password', 'salt', 'email', 'dob', 'recieve_emails', 'view_signatures') VALUES (:username, :password, :salt, :email, :dob, :recieve_emails, :view_signatures)

到

INSERT INTO users (`username`, `password`, `salt`, `email`, `dob`, `recieve_emails`, `view_signatures`) VALUES (:username, :password, :salt, :email, :dob, :recieve_emails, :view_signatures)

http://dev.mysql.com/doc/refman/5.0/en/identifiers.html

P.S：你的代碼確實有的if/else嵌套塊太多。考慮優化它們。人們可能會失去閱讀的能力。

來源

2014-02-16 09:38:11

謝謝你，完美的工作。 – user3186081

PDO插入錯誤 - 執行（array（））;

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