插入到C＃應用程序失敗的Access數據庫中

Question

我已經加入了兩個表值並將這些值插入到另一個表中，但插入不起作用。我使用的是Access數據庫，我使用下面的代碼：

string query = "select t2.date,t1.FlightNo,t1.Dept_Time,t1.Arr_Time,t1.Route,t1.[Destination 1],t1.[Destination 2],t1.[Destination 3],t1.[Destination 4] From [FlightNumber]as t1 inner join [schedule]as t2 on t1.FlightNo=t2.FlightNo"; 

OleDbCommand cmd = new OleDbCommand(query, con); 

OleDbDataAdapter adp = new OleDbDataAdapter(cmd); 
dt1 = new DataTable(); 
adp.Fill(dt1); 
con.Open(); 
string query2 = "Insert into Monday (date,[Flight_no],[Dept_time],[Arr_time],Route,[dest_1],dest2,dest3,dest4)values(@date,@flight,@dept,@arr,@route,@dest1,@dest2,@dest3,@dest4)"; 
for (int i = 0; i < dt1.Rows.Count; i++) 
{ 
    OleDbCommand cmd1 = new OleDbCommand(query2, con); 

    cmd.Parameters.AddWithValue("@date", SqlDbType.NVarChar).Value = dt1.Rows[i]["date"].ToString(); 
    cmd.Parameters.AddWithValue("@flight", dt1.Rows[i]["FlightNo"]); 
    cmd.Parameters.AddWithValue("@dept", dt1.Rows[i]["Dept_Time"]); 
    cmd.Parameters.AddWithValue("@arr", dt1.Rows[i]["Arr_Time"]); 
    cmd.Parameters.AddWithValue("@route", dt1.Rows[i]["Route"]); 
    cmd.Parameters.AddWithValue("@dest1", dt1.Rows[i]["Destination 1"]); 
    cmd.Parameters.AddWithValue("@dest2", dt1.Rows[i]["Destination 2"]); 
    cmd.Parameters.AddWithValue("@dest3", dt1.Rows[i]["Destination 3"]); 
    cmd.Parameters.AddWithValue("@dest4", dt1.Rows[i]["Destination 4"]); 

    cmd1.ExecuteNonQuery(); 
    con.Close(); 
    MessageBox.Show("successfully inserted");    
} 

Answer 1

DATE是訪問SQL一個reserved word，所以你需要用該列名在方括號中的INSERT命令（像你這樣用[Flight_no]，[Dept_time]等）。

string query2 = "Insert into Monday ([date], ... 

Answer 2

除了什麼戈德提及保留字日期，你可能會在性能更好，如果你不保持重建的命令和參數，特別是如果你有很多你想插入記錄。相反，這樣做......

string query2 = "Insert into Monday (date,[Flight_no],[Dept_time],[Arr_time],Route,[dest_1],dest2,dest3,dest4)values(@date,@flight,@dept,@arr,@route,@dest1,@dest2,@dest3,@dest4)"; 

//預構建的命令和參數ONCE
OleDbCommand的CMD1 =新的OleDbCommand（QUERY2，CON）;

cmd.Parameters.AddWithValue（「@ date」，dt1.Rows [i] [「date」]。ToString（））; cmd.Parameters.AddWithValue（「@ flight」，dt1.Rows [i] [「FlightNo」]）; cmd.Parameters.AddWithValue（「@ dept」，dt1.Rows [i] [「Dept_Time」]）; cmd.Parameters.AddWithValue（「@ arr」，dt1.Rows [i] [「Arr_Time」]）; cmd.Parameters.AddWithValue（「@ route」，dt1.Rows [i] [「Route」]）; cmd.Parameters.AddWithValue（「@ dest1」，dt1.Rows [i] [「Destination 1」]）; cmd.Parameters.AddWithValue（「@ dest2」，dt1.Rows [i] [「Destination 2」]）; cmd.Parameters.AddWithValue（「@ dest3」，dt1.Rows [i] [「Destination 3」]）; cmd.Parameters.AddWithValue（「@ dest4」，dt1.Rows [i] [「Destination 4」]）;

for (int i = 0; i < dt1.Rows.Count; i++) 
{ 
    cmd.Parameters[0].Value = dt1.Rows[i]["date"].ToString(); 
    cmd.Parameters[1].Value = dt1.Rows[i]["FlightNo"]); 
    cmd.Parameters[2].Value = dt1.Rows[i]["Dept_Time"]); 
    cmd.Parameters[3].Value = dt1.Rows[i]["Arr_Time"]); 
    cmd.Parameters[4].Value = dt1.Rows[i]["Route"]); 
    cmd.Parameters[5].Value = dt1.Rows[i]["Destination 1"]); 
    cmd.Parameters[6].Value = dt1.Rows[i]["Destination 2"]); 
    cmd.Parameters[7].Value = dt1.Rows[i]["Destination 3"]); 
    cmd.Parameters[8].Value = dt1.Rows[i]["Destination 4"]); 

    cmd1.ExecuteNonQuery(); 
} 

con.Close(); 
MessageBox.Show("successfully inserted");