按「Y」或「Y」一遍又一遍地重複我的代碼

Question

import java.util.Scanner; 
 
class Quiz4 { 
 
    public static void main(String args[]){ 
 
\t \t char repeat = userInput.charAt(0); 
 
\t \t do{ 
 

 
     Scanner input = new Scanner(System.in); 
 
     System.out.println("Enter a binary number "); 
 
     String binaryString =input.nextLine(); 
 

 
     if (binaryString.matches("[10]+")) { 
 
\t \t System.out.println ("You entered " +binaryString); 
 
      System.out.println("Its base of 10 equivalent is "+Integer.parseInt(binaryString,2)); 
 
     } else { 
 
      System.out.println ("Try again "); 
 
      }while (repeat == 'Y' || repeat == 'y'); 
 
     } 
 
    } 
 
}

我寫的是二進制轉換爲十進制代碼，我已經得到了幾乎一切除了做我必須做確保程序繼續工作，直到用戶提示停止。我不知道如何將它應用到我的代碼。我知道我使用了do/while循環，但我不知道如何應用它。

import java.util.Scanner; 
class Quiz4 { 
    public static void main(String args[]){ 
     Scanner input = new Scanner(System.in); 
     System.out.println("Enter a binary number "); 
     String binaryString =input.nextLine(); 
     if (binaryString.matches("[10]+")) { 
      System.out.println ("You entered " +binaryString); 
      System.out.println("Its base of 10 equivalent is "+Integer.parseInt(binaryString,2)); 
     } else { 
      System.out.println ("Try again "); 
     } 
    } 
} 

Answer 1

您的代碼有2個問題。 1）重複在循環中沒有改變，所以循環將永遠循環或只運行一次。爲了解決這個問題，在你的循環中的某個時刻，你需要改變重複的步驟，作爲用戶詢問他們是否繼續前進的最後一個反應。這使我感到2）你永遠不會問用戶他們是否想要再次轉換。詢問用戶是否要繼續下去，指定他們必須用y或響應，然後存儲他們在重複

Answer 2

使用響應在控制檯上做while循環

import java.util.Scanner; 
class Main { 
    public static void main(String args[]){ 
     Scanner input = new Scanner(System.in); 
     String str; 
     do{ 
      System.out.println("Enter a binary number "); 
      String binaryString =input.nextLine(); 
      if (binaryString.matches("[10]+")) { 
       System.out.println ("You entered " +binaryString); 
       System.out.println("Its base of 10 equivalent is "+Integer.parseInt(binaryString,2)); 
      } else { 
       System.out.println ("Try again "); 
      } 
      System.out.println("Do you want to continue ? Press Y or y"); 
      str = input.nextLine(); 
     }while(str.charAt(0) == 'Y'||str.charAt(0) == 'y'); 

     System.out.println("Exiting"); 
    } 
} 

輸出。

Enter a binary number 
100 
You entered 100 
Its base of 10 equivalent is 4 
Do you want to continue ? Press Y or y 
y 
Enter a binary number 
102 
Try again 
Do you want to continue ? Press Y or y 
y 
Enter a binary number 
111 
You entered 111 
Its base of 10 equivalent is 7 
Do you want to continue ? Press Y or y 
Y 
Enter a binary number 
110 
You entered 110 
Its base of 10 equivalent is 6 
Do you want to continue ? Press Y or y 
n 
Exiting