Python的sqlite3的 - cursor.execute - 沒有錯誤

Question

這是一段代碼，這需要執行如下功能：從每個表搜索與列在數據庫中

• 轉儲所有的表名或者經緯度在
• 存儲這些共ORDS作爲JSON文件

的代碼進行了測試，一個單一的數據庫上工作。然而，一旦將它放入另一段用不同數據庫調用它的代碼中，它現在不會輸入第49行。但是沒有錯誤，所以我很難看出問題是什麼，因爲我沒有改變任何東西。

代碼段第48行是底線 -

cursor.execute("SELECT name FROM sqlite_master WHERE type='table'") 
print (cursor) 
    for tablerow in cursor.fetchall(): 

我在/ tmp /目錄運行此因使用SQLite不是臨時在外打工以前的錯誤。

有任何問題請諮詢他們。

謝謝！

#!/usr/bin/python 
# -*- coding: utf-8 -*- 

import sqlite3 
import os 
import sys 

filename = sys.argv[1] 


def validateFile(filename): 
    filename, fileExt = os.path.splitext(filename) 
    print ("[Jconsole] Python: Filename being tested - " + filename) 
    if fileExt == '.db': 
     databases(filename) 
    elif fileExt == '.json': 
     jsons(fileExt) 
    elif fileExt == '': 
     blank() 
    else: 
     print ('Unsupported format') 
     print (fileExt) 


def validate(number): 
    try: 
     number = float(number) 
     if -90 <= number <= 180: 
      return True 
     else: 
      return False 
    except ValueError: 
     pass 


def databases(filename): 
    dbName = sys.argv[2] 
    print (dbName) 
    idCounter = 0 
    mainList = [] 
    lat = 0 
    lon = 0 
    with sqlite3.connect(filename) as conn: 
     conn.row_factory = sqlite3.Row 
     cursor = conn.cursor() 
     cursor.execute("SELECT name FROM sqlite_master WHERE type='table'") 
     print (cursor) 
     for tablerow in cursor.fetchall(): 
      print ("YAY1") 
      table = tablerow[0] 
      cursor.execute('SELECT * FROM {t}'.format(t=table)) 
      for row in cursor: 
       print(row) 
       print ("YAY") 
       tempList = [] 
       for field in row.keys(): 
        tempList.append(str(field)) 
        tempList.append(str(row[field])) 
       for i in tempList: 
        if i in ('latitude', 'Latitude'): 
         index = tempList.index(i) 
         if validate(tempList[index + 1]): 
          idCounter += 1 
          tempList.append(idCounter) 
          (current_item, next_item) = \ 
           (tempList[index], tempList[index + 1]) 
          lat = next_item 
        if i in ('longitude', 'Longitude'): 
         index = tempList.index(i) 
         if validate(tempList[index + 1]): 
          (current_item, next_item) = \ 
           (tempList[index], tempList[index + 1]) 
          lon = next_item 
        result = '{ "id": ' + str(idCounter) \ 
         + ', "content": "' + dbName + '", "title": "' \ 
         + str(lat) + '", "className": "' + str(lon) \ 
         + '", "type": "box"},' 
        mainList.append(result) 
    file = open('appData.json', 'a') 
    for item in mainList: 
     file.write('%s\n' % item) 
    file.close() 


    # { 
    # ...."id": 1, 
    # ...."content": "<a class='thumbnail' href='./img/thumbs/thumb_IMG_20161102_151122.jpg'>IMG_20161102_151122.jpg</><span><img src='./img/thumbs/thumb_IMG_20161102_151122.jpg' border='0' /></span></a>", 
    # ...."title": "50.7700721944444", 
    # ...."className": "-0.8727045", 
    # ...."start": "2016-11-02 15:11:22", 
    # ...."type": "box" 
    # }, 

def jsons(filename): 
    print ('JSON') 
def blank(): 
    print ('blank') 

validateFile(filename) 

Answer 1

固定。

的問題是在這裏

filename, fileExt = os.path.splitext(filename) 

沒有，所以當SQLite的搜查沒有發現該文件的文件擴展名的文件名可變正被改寫。

奇怪的是沒有錯誤出現，但現在通過將文件名var更改爲filename1來修復它。