fPython：從一個隨機的字母列表中創建一個新列表

Question

letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']#alphabet 
bag_o_letters = []#letters to chose from 
letter_count = [9, 2, 2, 4, 12, 2, 3, 2, 9, 1, 1, 4, 2, 6, 8, 2, 1, 6, 4, 6, 4, 2, 2, 1, 2, 1]#random indexes to chose from 
for x in range(26):#loops through the random index of letter_count 
    for i in range(letter_count[x]):#chooses the index 
     bag_o_letters.append(letters[x])#appends the index of the letter to bag_o_letters 
     rack = []#list for the person to see 
     for a in range(7):#makes the list 7 letters long 
      rack.append(bag_o_letters.pop(random.randint(0,len(letters)-1)))#appends the letter to rack(supposedly...) 
print(rack) 

在剛剛閱讀的代碼中，應該選擇隨機字母，並將這些字母中的7個放在可以看到的機架中。它顯示了我多次查看的錯誤，但我看不出錯在哪裏。

I put comments on the side to understand the code.

它顯示了這個錯誤：

rack.append(bag_of_letters.pop(random.randint(0,len(letters)-1))) 
IndexError: pop index out of range 

Can someone please help?

After this code, I am going to make a input statement for the user to make a word from those letters.

Answer 1

你從letters長度選擇指數到pop爲bag_of_letters這顯然更大。

而應該做的：

rack.append(bag_of_letters.pop(random.randint(0, len(bag_of_letters)-1))) 
#             ^^^^^^^^^^^^^^ 

---

不過，也有可能是更多的問題與您的代碼。我會建議你的代碼或random.shuffle一行在列表的副本使用random.sample，然後片截至7指數都將會給你7個隨機選擇字母：

import random 

print(random.sample(letters, 7)) 
# ['m', 'u', 'l', 'z', 'r', 'd', 'x'] 

---

import random 

letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] 
letters_copy = letters[:] 
random.shuffle(letters_copy) 
print(letters_copy[:7]) 
# ['c', 'e', 'x', 'b', 'w', 'f', 'v'] 

Answer 2

第一次通過循環，您將一個值附加到bag_of_letters，然後嘗試彈出random.randint(0,len(letters)-1)的索引。它還沒有那麼多元素可以流行起來。而不是這種方法，你可以列出所需的長度和樣本：

letters = ['a', ...]#alphabet 
letter_count = [9, ...]#random indexes to chose from 
bag_of_letters = [l*c for l,c in zip(letters, letter_count)] 
... 
rack = random.sample(bag_o_letters, 7) 

Answer 3

所以我認爲這是爲了像拼字遊戲？您的問題是，您要從letters列表中選擇一個隨機索引，而不是bag_o_letters。也許試試這個：

rack = [] 
for i in range(7): 
    index = random.randint(0, len(bag_o_letter) - 1) 
    rack.append(bag_o_letters.pop(index)) 

Answer 4

爲什麼不能做這樣的事情：

letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] 
letter_count = [9, 2, 2, 4, 12, 2, 3, 2, 9, 1, 1, 4, 2, 6, 8, 2, 1, 6, 4, 6, 4, 2, 2, 1, 2, 1]#random indexes to chose from 

from random import shuffle 
all_letters = list(''.join([l*c for l,c in zip(letters, letter_count)])) 
shuffle(all_letters) 

for i in range(int(len(all_letters)/7)): 
    print all_letters[i*7:(i+1)*7] 

Answer 5

的IndexError預計：

pop(...) L.pop([index]) -> item -- remove and return item at index (default last). Raises IndexError if list is empty or index is out of range.

您需要從通話的範圍減去1 random()之後每pop()。現在你這樣做是：

l = [1,2,3] 

random_idx = 2 
l.pop(random_idx) 
>>> l == [1,3] 

random_idx = 3 
l.pop(random_idx) 
>>>> IndexError: pop index out of range 

所以取而代之，基於len(bag_o_letter)，而不是len(letter)pop()。